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Leto [7]
3 years ago
6

Rules for naming ionic compounds wiht transition metal

Chemistry
1 answer:
Aneli [31]3 years ago
3 0

Rules for naming ionic compounds with transition metal requires the elementary name of metal followed the anion name with suffix ide.

<h3>What are ionic compounds?</h3>

Ionic compounds are made up of ions, which are charged particles that occur when an atom (or group of atoms) acquires or loses electrons. Generally cations are metals and anions are non metals in it.

Following rules will be considered during naming:

  • First determine the metal's elemental name.
  • Give the nonmetal its elemental name and the suffix -ide.
  • Use roman numerals to denote positive charge when naming metals that can have distinct oxidation states.
  • Name the polyatomic ions according to their names.

Hence rules for naming are listed above.

To know more about nomenclature of ionic compounds, visit the below link:

brainly.com/question/18672152

#SPJ4

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Draw the structure of the following three isomeric esters with chemical formula C7H12O2. Ester #1: methyl 1-methylcyclobutanecar
marissa [1.9K]

Answer:

The following three isomeric structure are given below.

Explanation:

Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂

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6 0
3 years ago
What is the rate constant of a first-order reaction that takes 143 seconds for the reactant concentration to drop to half of its
algol [13]

Answer:

k = 4.85 x 10⁻³ / s

Explanation:

For a first order reaction we have two very important equations we need to memorize:

ln ( N/N₀ ) = -kt

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0.693/ k = t₁/₂

where k is the rate constant and t i is the halflife which can be derived from the first equation.

0.693/ k = t₁/₂   ⇒  k = 0.693 / t₁/₂  

k = 0.693 / 143 s = 4.85 x 10⁻³ / s

3 0
3 years ago
The half life of iodine-125 is 60 days. What was the initial amount of iodine-125 if you have 4.5 grams after 360 days?
ValentinkaMS [17]

Answer:

288 grams

Explanation:

The amount of any radiative substance left after some time is calculated by

amount left = x/2^n

where x is the initial amount of substance

n is the number of half lives

one half live is the time in which amount of substance reduce to half of its initial value.

------------------------------------------------------

amount left = 4.5 grams

half life of  iodine-125 = 60 days

total time in which substance reduced to 4.5 grams  = 360 days

thus,

number of half life in 60 days = 360/60 = 6

thus, there are period of 6 half lives

in each half life the amount of substance reduces to its previous half

let the initial amount be x grams

using the formula

amount left = x/2^n

4.5 = x/2^6 \\ 4.5 = x/64\\x = 4.5*64 = 288

Thus, 288 grams was the initial amount of iodine-125

6 0
3 years ago
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