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statuscvo [17]
3 years ago
14

An increase in the temperature of a solution usually: a)increases the boiling point. b)increases the solubility of a gas in the

solution. c)increases the solubility of a solid solute in the solution. d)decreases the solubility of a solid solute in the solution. e)decreases the solubility of a liquid solute in the solution.
Chemistry
1 answer:
irina [24]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

Relation between kinetic energy and temperature is as follows.

                      K.E = \frac{3}{2}kT

Since, kinetic energy is directly proportional to temperature. So, when there will be increase in temperature then this will also lead to increase in kinetic energy of the molecules of a substance.

So, when a solid substance is dissolved in a solution whose temperature is increased then molecules of the solid will also gain kinetic energy. As a result, more number of collisions will occur due to which bond between the molecules of solid will break.

Therefore, there will be increase in solubility of the solid.

Thus, we can conclude that an increase in the temperature of a solution usually increases the solubility of a solid solute in the solution.

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If a person weighs 63.4 KG they will weigh 139.773 but if you estimate it which in most cases you do it would be 139.8 :)
3 0
1 year ago
When 150. g zinc sulfide are burned in excess oxygen, 68.5 g of zinc oxide are actually produced, along with sulfur dioxide. Det
Bumek [7]

%yield = 54.6%

<h3>Further explanation</h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

(theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

<h3 />

Reaction

2ZnS+3O₂ ⇒ 2ZnO+2SO₂

MW ZnS = 97.474 g/mol

  • mol ZnS

\tt \dfrac{150}{97.474}=1.54

MW ZnO = 81.38 g/mol

  • mol ZnO (from mol ZnS as limiting reactant, O₂ excess)

\tt \dfrac{2}{2}\times 1.54=1.54

  • Actual ZnO produced

\tt 1.54\times 81.38=125.33~g

Theoretical production = 125.388

  • %yield

\tt \dfrac{68.5}{125.33}\times 100\%=\boxed{\bold{54.6\%}}

4 0
3 years ago
A solution with [ OH] of 5 x 10-3 has a pH of
CaHeK987 [17]

Answer:

11·699

Explanation:

Given the concentration of hydroxide ion in the solution is 5 × 10^{-3} M

Assuming the temperature at which it is asked to find the pH of the solution be 298 K

<h3>At 298 K the dissociation constant of water is 10^{-14} </h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>

∴ pOH of the given solution = - log(5 × 10^{-3} = -0·699 + 3 = 2·301

   pH of the given solution = 14 - 2·301 = 11·699

∴ pH of the solution = 11·699                                  

8 0
3 years ago
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Answer:

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Explanation:

8 0
3 years ago
What is the product of SO2+H2O. ​
Mariulka [41]

Answer:

H2O + SO2 → H2SO3

Explanation:

H2O + SO2 → H2SO3

6 0
3 years ago
Read 2 more answers
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