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Kaylis [27]
3 years ago
8

A student wants to know which part of his local beach contains the most turtle nests during nesting season. He researches turtle

nesting and plans his experiment. Once his experiment is completed, he gathers his evidence and analyzes it to form a conclusion.
What part of the scientific method is he missing from this investigation?

Ask a question.
Construct a hypothesis.
Do background research.
Analyze the evidence.
Chemistry
2 answers:
NikAS [45]3 years ago
4 0
He did not create a hypothesis

creativ13 [48]3 years ago
4 0

B) Construct an Hypothesis

I know this because I got it right on my test along with 100%

Please mark brainliest and I hope you do well :)

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Which of the following measurements is expressed to three significant figures? 7.30 × 10–7 km 0.007 m 7077 mg 0.070 mm
Sonbull [250]

7.30 x 10^-7 km. the others have 4 significant figures.

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Ice melts to form water. And water freezes to form ice. Choose the TRUE statement about these changes.
Dmitrij [34]

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A. Both freezing and melting are physical changes.

Explanation:

Even if you were to freeze water, the molecules are still water molecules, and vise versa with melting it.

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A mercury thermometer is used to take four temperatures of a solution
anastassius [24]

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scale. Mercury thermometers can be used to determine body, liquid, and vapor temperature.

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You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the
Ipatiy [6.2K]
P1V1/T1=P2V2/T2   P2=1/2 P1 V1=1 T1=298K

1 P1/298= (1/2) P1V2/373  cross P1

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3 years ago
What type of radioactive decay will the isotopes 13B and 188Au most likely undergo?
scoundrel [369]

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A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).

Now let us look at the N/P ratio of each atom;

For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6

For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4

For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.

For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.

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