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Mazyrski [523]
3 years ago
5

What is the pH of a solution with [H+]=6.2x10-9 M?

Chemistry
1 answer:
Serga [27]3 years ago
3 0

Answer: 8.2

Explanation:

pH of a solution is  - Log [ H+].

pH = - Log [ 6.2 x 10-9 M]

     = 9 - 0.7924

pH =  8.24 approx 8.2

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​What is the concentration of the solution prepared by dissolving 2.35 g of KBr (M = 119 g/mol) in 250 mL of water? 
dusya [7]

Answer:

The concentration of KBr is  C = 0.07899 \ mol   L^{-1}

Explanation:

From the question we are told that

      The mass of KBr is  m_{KBr}  = 2.35 \ g

       The molar mass of KBr is  M_{KBr} =  119 g/mol

       Volume of water is V = 250 \ mL = 250 *10^{-3} =  0.250 \ L

This implies that the volume of  the solution is  V = 250 mL

The number of moles of KBr is

         n = \frac{m_{KBr}}{M_{KBr}}

Substituting values

         n =  \frac{2.35}{119}

        n = 0.01975 \ mol

The concentration of KBr is mathematically represented as

                C = \frac{0.01975}{0.250}

                C = 0.07899 \ mol   L^{-1}

3 0
3 years ago
Analysis of the water content of a lake found in the desert showed that it contained 17.5 percent chloride ion, and has a densit
tankabanditka [31]

Answer:

The molarity is 6.0 M.

Explanation:

<em>The </em><em>concentration</em><em> of a solution is the amount of solute present in a given amount  of solvent, or a given amount of solution.</em>

In this problem, we are asked to convert percent by mass to molarity, which are two different concentration units.

<em>The </em><em>percent by mass </em><em>is the ratio of the mass of a solute to the mass of the solution, multiplied by 100 percent.</em> On the other hand, <em>molarity (M)</em><em> is defined as the number of moles of solute per liter of solution.</em>

If we have 17.15 percent chloride ion, that means that we have 17.15 grams of chloride ion in 100 grams of solution. The density provided is the density of the solution, so we calculate how many mL correspond to 100 grams of solution:

1.23 g ----------- 1 mL

100 g ------------ <u>x= 81.3 mL</u>

Therefore, 17.5 grams of chloride ion are contained in 81.3 mL. Now we need to convert these grams into moles.

The atomic mass of chlorine is 35.5 g/mol:

35.5 g --------------- 1 mol

17.5 g --------------- <u>x= 0. 49 mol</u>

This 0.49 moles are contained in 81.13 mL, the definition of molarity says that this moles are contained in a liter (or what is the same, 1000 mL):

81.3 mL --------------- 0.49 mol

1000 mL ------------- x= 6.0 M

The molarity of the chloride ion will be 6.0 M.

5 0
3 years ago
Calculate the atomic mass of gallium, symbol Ga. Gallium has two isotopes: Ga-69 and Ga-71. The relative abundance of Ga-69 is 6
amm1812

Answer:

The atomic mass of gallium (Ga) = <u>69.723 g/mol</u>

Explanation:

Given: Two isotopes of Gallium (Ga) are Gallium-69 (⁶⁹Ga) and Gallium-71 (⁷¹Ga)

<u>For ⁶⁹Ga: </u>

Relative abundance = 60.12% = 60.12 ÷ 100 = 0.6012; Atomic mass = 68.9257 g/mol

<u>For ⁷¹Ga:</u>

Relative abundance = 39.88% = 39.88 ÷ 100 = 0.3988; Atomic mass = 70.9249 g/mol

∴ The atomic mass of Ga = (Relative abundance of ⁶⁹Ga × Atomic mass of ⁶⁹Ga) + (Relative abundance of ⁷¹Ga × Atomic mass of ⁷¹Ga)

⇒ Atomic mass of Ga = (0.6012 × 68.9257 g/mol) + (0.3988 × 70.9249 g/mol) = <u>69.723 g/mol</u>

<u>Therefore, the atomic mass of gallium (Ga) = 69.723 g/mol</u>

8 0
3 years ago
A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur
Ymorist [56]

<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 30 g

m_2 = mass of water = 100 g

T_{final} = final temperature = 25°C

T_1 = initial temperature of metal = 110°C

T_2 = initial temperature of water = 20.0°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]

c_1=0.821J/g^oC

Hence, the specific heat of metal is 0.821 J/g°C

8 0
3 years ago
What is the name of a solution whose concentration of solute is equal to the maximum concentration that is predicted from the so
faltersainse [42]

<u>Answer:</u> The correct answer is saturated solution.

<u>Explanation:</u>

For the given options:

Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.

Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.

Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent.  The concentration of the solute particles that can be dissolved in a solution is maximum.

Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.

From the above information, we conclude that the given solution is saturated solution.

7 0
3 years ago
Read 2 more answers
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