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melomori [17]
3 years ago
5

WILL GIVE BRAINLIEST

Chemistry
2 answers:
Marianna [84]3 years ago
7 0
Answer:

B, C, and D

Explanation:

A is the only one in which two components are being combined. The point is to separate the mixture, so that is the only one that would not apply.
White raven [17]3 years ago
3 0

Answer:

b, c, and d is correct

Explanation:

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How would I solve this kind of equation ?3.346 x 10^6km to m
mash [69]

Answer:

Explanation:

This question is asking to convert a measurement in kilometers to meters

5 0
3 years ago
Factors that affect the acceleration of an object include the..?
iren [92.7K]
As per the Equation,
Acceleration = Force/Mass

We Can Conclude That,
Acceleration of an object is affected by A). Net Force Acting On the Object and C). Object's Mass.

!! Hope It Helps !!
7 0
3 years ago
What is the final [Na+] in a solution prepared by mixing 70.0 mL of 3.00 M Na2SO4 with 30.0 mL of 1.00 M NaCl?
Lynna [10]

Answer:

4.5 M

Explanation:

70.0 ml was mixed in 3.00 M of Na2SO4

30.0 ml was mixed in 1.00 M of NACL

The first step is to convert 70 ml to liters

= 70/1000

= 0.07 liters

The formular for molarity is

moles/liters

The number of moles in Na2S04 can be calculated as follows

Let y represent the number of moles

3M= y moles/0.07

= 3×0.07

= 0.21 moles

Since Na2So4 has 2 moles of Na then the number of moles is

= 2×0.21

= 0.42 moles

Convert 30ml to liters

= 30/1000

= 0.03 liters

The number of moles in Nacl can be calculated as follows

Let y represent the number of moles

1M= y moles/0.03

= 1×0.03

= 0.03 moles

Since Nacl has 1 mole of Na then the number of moles is

= 1 × 0.03

= 0.03 moles

Therefore the final Na+ can be calculated as follows

Total moles = 0.03 moles + 0.42 moles

= 0.45 moles

Total liters= 0.07 liters + 0.03 liters

= 0.1 liters

Na+ = 0.45/0.1

= 4.5 M

Hence the final Na+ in the solution is 4.5 M

7 0
4 years ago
Write the electron configurations for each of the following elements:
Stolb23 [73]

Answer:

  • (a) E.C - 2,8,8,3
  • (b) E.C - 2,8,8,4
  • (c) E.C - 2,8,8,6
  • (d) E.C - 2,8,8,8
  • (e) E.C - 2,8,8,8,18
7 0
4 years ago
Nitrogen dioxide and water react to produce nitric acid, HNO3,
maw [93]

Answer:

Explanation:

a )

3NO₂(g) + H₂O(l) — -→ 2HNO₃(aq) + NO(g)

3 x 46 g       18 g            2 x 63 g       30 g

138 g of NO₂ requires 18 g of H₂O

28 g of NO₂ requires ( 18 / 138) x 28

= 3.65 g of H₂O.

b )

18 g of H₂O produces 30 g of NO gas

15.8 g of H₂O produces ( 30/18 ) x 15.8

= 26.33 g of NO gas .

c )

138 g of NO₂ produces 126 g of HNO₃

8.25 g  of NO₂ produces (126 / 138 ) x 8.25

= 7.53 g of HNO₃

7 0
3 years ago
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