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cluponka [151]
3 years ago
7

What is the volume needed to make 4.2M solution using 6.5 mol NaCl?

Chemistry
2 answers:
hram777 [196]3 years ago
8 0
Molarity is given as,

                             Molarity  =  Moles / Volume of Solution   ---- (1)

Given Data:
                   Molarity  =  4.2 mol.dm⁻³

                   Moles     =  6.5 mol

To Find:
                  Volume  =  ?

Solution:
              Solving Eq. 1 for Volume,

                              Volume  =  Moles ÷ Molarity
Putting Values,
                              Volume  =  6.5 mol ÷ 4.2 mol.dm⁻³ \

                              Volume  =  1.54 dm⁻³                    ∴ 1 dm³  =  1 L

strojnjashka [21]3 years ago
7 0
Molarity is defined as the number of moles of solute in volume of 1 L solution.
Molarity of NaCl is 4.2 M
the number of NaCl moles present is 6.5 mol
the volume of 4.2 moles is dissolved in 1 L solution
therefore volume required for 6.5 mol is - 6.5 mol / 4.2 mol/L = 1.5 L 
therefore volume required is 1.5 L
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aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is
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There is 9.6 grams of CO2 produced

Explanation:

Step 1: Data given

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Step 2: The reaction

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Step 3: Calculate number of moles

Moles = mass / molar mass

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Moles methane = 0.343 moles

Moles oxygen = 13.9 grams / 32.0 g/mol

Moles oxygen = 0.434 moles

For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O

O2 is the limiting reactant. It will completely react (0.434 moles).

There will react 0.434/2 = 0.217 moles CH4

There will remain 0.343-0.217 = 0.126 moles CH4

There will be produced 0.434 moles of H2O and

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Mass = moles * molar mass

Mass CO2 = 0.217 moles ¨44.01 g/mol

Mass CO2 = 9.6 grams

Mass H2O = 0.434 moles * 18.02

Mass H2O = 7.8 grams

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