Question

An object is constrained by a cord to move in a circular path of radius 0.5m on a horizontal frictionless surface. The cord will break if its tension exceeds 16N. The maximum kinetic energy the object can have is _______?

Answer 1

Answer:

maximum kientcie energy is 4 Joules.

Explanation:

When an object moves in a circular path, the tension acting on the cord is equal to the centripetal force.

Here, the cord will break if its tension exceeds 16 N and the radius of the circular path is 0.5 m. So,

$\dfrac{mv^2}{r}=16\\\\mv^2=16\times r\\\\mv^2=16\times 0.5\\\\mv^2=8$.......(1)

We know that the kinetic energy of the object is given by :

$E=\dfrac{1}{2}mv^2$

Putting equation (1) in above equation as :

$E=\dfrac{1}{2}\times 8\\\\E=4\ J$

So, the maximum kinetic energy the object can have is 4 Joules.