Answer: The ratio of atoms of potassium to ratio of atoms of oxygen is 4:2
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed, and remains conserved. The mass of products must be same as that of the reactants.
Thus the number of atoms of each element must be same on both sides of the equation so as to keep the mass same and thus balanced chemical equations are written.
K exists as atoms and oxygen exist as molecule which consists of 2 atoms. The ratio of number of atoms on both sides of the reaction are same and thus the ratio of atoms of potassium to ratio of atoms of oxygen is 4:2.
Answer:
2.84 g's with the remaining 1 g coming from gravity (3.84 g's)
Explanation:
period of oscillation while waiting (T1) = 2.45 s
period of oscillation at liftoff (T2) = 1.25 s
period of a pendulum (T) =2π. 
where
- L = length
- a = acceleration
therefore the ration of the periods while on ground and at take off will be
=(2π
) / (2π
)
where
- a1 = acceleration on ground while waiting
- a2 = acceleration during liftoff
= 
squaring both sides we have
= 
= 
assuming that the acceleration on ground a1 = 9.8 m/s^{2}
= 
a2 = 9.8 x 
substituting the values of T1 and T2 into the above we have
a2 = 9.8 x 
a2 = 9.8 x 3.84
take note that 1 g = 9.8 m/s^{2} therefore the above becomes
a2 = 3.84 g's
Hence assuming the rock is still close to the ground during lift off, the acceleration of the rocket would be 2.84 g's with the remaining 1 g coming from gravity.
Atom absorbs energy when it goes into higher orbitals from their "Ground States"
Hope this helps!
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