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KengaRu [80]
4 years ago
10

Why do high water temperatures reduce the amount of fish in a water ecosystem? A. High temperatures decrease the nutriet level B

. High temperatures can lower pH of the water C. High temperatures can decrease turbidity D. High temperatures can reduce the amount of dissolved oxygen in the water
Physics
1 answer:
vitfil [10]4 years ago
8 0

Answer:

The correct option is  D

Explanation:

Generally when there is an increase in temperature of water the solubility of oxygen decrease and this would in turn decrease the amount of fish in water due to the fact that fish require oxygen soluble oxygen to survive

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The equation below is for potassium oxide.
ValentinkaMS [17]

Answer: The ratio of atoms of potassium to ratio of atoms of oxygen is 4:2

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed, and remains conserved. The mass of products must be same as that of the reactants.

Thus the number of atoms of each element must be same on both sides of the equation so as to keep the mass same and thus balanced chemical equations are written.

K exists as atoms and oxygen exist as molecule which consists of 2 atoms. The ratio of number of atoms on both sides of the reaction are same and thus the ratio of atoms of potassium to ratio of atoms of oxygen is 4:2.

5 0
3 years ago
Read 2 more answers
An object is on a spring (k 7.3 N/m). The maximum speed of the object is .25 m/sec, and the maximum displacement is 85 cm. What
denpristay [2]
 i think it should be 0.25kg
8 0
4 years ago
An astronaut notices that a pendulum which took 2.45 s for a complete cycle of swing when the rocket was waiting on the launch p
klio [65]

Answer:

2.84 g's with the remaining 1 g coming from gravity (3.84 g's)

Explanation:

period of oscillation while waiting (T1) = 2.45 s

period of oscillation at liftoff (T2) = 1.25 s

period of a pendulum (T) =2π. \sqrt{\frac{L}{a} }

where

  • L = length
  • a = acceleration

therefore the ration of the periods while on ground and at take off will be

\frac{T1}{T2} =(2π \sqrt{\frac{L}{a1} } ) /  (2π\sqrt{\frac{L}{a2} })

where

  • a1 = acceleration on ground while waiting
  • a2 = acceleration during liftoff

\frac{T1}{T2} = \frac{\sqrt{\frac{L}{a1} }}{\sqrt{\frac{L}{a2} }}

squaring both sides we have

(\frac{T1}{T2})^{2} = \frac{\frac{L}{a1} }{\frac{L}{a2} }

(\frac{T1}{T2})^{2} = \frac{a2}{a1}

assuming that the acceleration on ground a1 = 9.8 m/s^{2}

(\frac{T1}{T2})^{2} = \frac{a2}{9.8}

a2 = 9.8 x (\frac{T1}{T2})^{2}

substituting the values of T1 and T2 into the above we have

a2 = 9.8 x (\frac{2.45}{1.25})^{2}

a2 = 9.8 x 3.84

take note that 1 g = 9.8 m/s^{2} therefore the above becomes

a2 = 3.84 g's

Hence assuming the rock is still close to the ground during lift off, the acceleration of the rocket would be 2.84 g's with the remaining 1 g coming from gravity.

5 0
3 years ago
When an atom absorbs energy the electrons move from their?
alukav5142 [94]
Atom absorbs energy when it goes into higher orbitals from their "Ground States"

Hope this helps!
8 0
4 years ago
Sound travels faster in: steel water sir
alukav5142 [94]
Sound travels better in water
8 0
3 years ago
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