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Dmitry [639]
3 years ago
15

Simplify 2y-6x+5+4y What is the answer?

Mathematics
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

Answer = −6x+6y+5

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In Triangle ABC, the length of Segment AB is equal to the length of segment AC. The length of segment BC is 4 less than twice th
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Step-by-step explanation:

Let x be the length of segment AB.

Then the length of segment BC is (2x - 4).

The length of segment AC is x.

We know that x + (2x - 4) + x = 52.

Therefore 4x - 4 = 52, 4x = 56, x = 14.

Hence the length of segment AB is 14.

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Determine if the triangles, CEG and DEF ,are similar. If so, identify the similarity
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A

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AA similarity means 2 angles must be similar.

Angle 1: Angle E is the same for both triangles

Angle 2: Angle F and angle G are congruent because they both have right angle markings so they are both 90 degrees.  

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A equal t added to 258<br><br><br>write the sentence as an equal ​
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A=t+258

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3 years ago
Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
4 years ago
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