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OLga [1]
3 years ago
8

It is necessary to determine the specific heat of an unknown object. The mass of the object is 201.0 g. It is determined experim

entally that it takes 15.0 J to raise the temperature 10.0 ° C. What is the specific heat of the object?
Physics
2 answers:
navik [9.2K]3 years ago
6 0
Mass = 0.201kg
Energy = 15J
temperature change = 10C

Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)

we can rearrange this to make specific heat capacity the subject

c =\frac{E}{m\theta}

c =\frac{15}{2.01}
c =7.46268657

aliina [53]3 years ago
5 0

Answer:

The specific heat of the object is 0.0074 J/(g °C)

Explanation:

Data

mass, m = 201 g

Heat, Q = 15 J

temperature change, ΔT = 10 °C

specific heat, cp = ?

The equation that relates these variables is:

Q = m*cp*ΔT

Solving for specific heat we get:

cp = Q/(m*ΔT)

Replacing with data (units are ommited):

cp = 15/(201*10)

cp = 0.0074 J/(g °C)

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2 years ago
A negatively charged balloon has 4 μC of charge. How many excess electrons are on this bal- loon? The elemental charge is 1.6 ×
bagirrra123 [75]
Data:

The charge of a body depends on the amount of electrons it gains or loses. Q = n * e, where "Q" is charge, "n" is the number of plus or minus electrons, and "e" is the fundamental charge of an electron 1,6 * 10 ^{-19}C<span>. To know if the body has gained or lost, we look at the signal of its charge, remembering that the electron is negative. The charge of the body is 4 μC (positive), so there is a lack of electrons! 

Q = 4 </span>μC → Q = 4*10^{-6}
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We have:
</span>Q = n*e
n =  \frac{Q}{e}
n =  \frac{4*10^{-6}}{1,6 * 10 ^{-19}}
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7 0
3 years ago
Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.83 ✕ 105 m/s in the positive x-direction. Thou
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Answer:

F=2.84*10^{-26}N  & -y direction

F=2.84*10^{-26}N & +y direction

Explanation:

From the question we are told that:

Speed of electron V_e=3.83 * 10^5 m/s +x direction

Earths magnetic field B_e=3.04 * 10^-^8 +z direction

a)

Generally the equation for magnetic force F_m is mathematically given by

F=q(V_e*B_e)

where

q=1.6*10^{-19}c\\\=i*\=z=-\=j

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N  -y direction

b)

Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by

\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

\=F'=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N & +y direction

5 0
3 years ago
NEED ANSWER NOW PLZ WILL MARK BRAINLIEST
PilotLPTM [1.2K]
I'm like 89% sure that the answer is C.
8 0
3 years ago
Read 2 more answers
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