Ask question

Ask question

All categories

2 years ago

8

A researcher measures the thickness of a layer of benzene (n = 1.50) floating on water by shining monochromatic light onto the f

ilm and varying the wavelength of the light. she finds that light of wavelength 600 nm is reflected most strongly from the film. part a what does she calculate for the minimum thickness of the film? express your answer with the appropriate units.

1 answer:

NNADVOKAT [17]2 years ago

5 0

Answer:

Explanation:

This problem relates to interference of light in thin films .

The condition of bright fringe in thin films which is sandwitched by two layers of medium having lesser refractive index is as follows.

2nt = (2n+1) λ / 2 , n is refractive index of thin layer , t is its thickness , λ is wavelength of light .

2 x 1.5 t = λ / 2 , if n = 0 for minimum thickness.

2 x 1.5 t = 600 / 2 nm

t = 100 nm .

You might be interested in

Calculate the magnitude of the acceleration of Io due to the gravitational force exerted by Jupiter. [Show all work, including t

galina1969 [7]

The magnitude of the acceleration due to the gravitational force exerted by Jupiter is 25.91 m/s².

<h3>What is acceleration due to gravity?</h3>

This is the acceleration of a body under a free fall due to influence of gravity.

The magnitude of the acceleration due to the gravitational force exerted by Jupiter is calculated as follows;

$F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}$

where;

M is mass of Jupiter
R is the radius of Jupiter
G is universal constant

$g = \frac{6.67 \times 10^{-11} \times 1.8986 \times 10^{27}}{(69,911 \times 10^3)^2} \\\\g = 25.91 \ m/s^2$

Thus, the magnitude of the acceleration due to the gravitational force exerted by Jupiter is 25.91 m/s².

Learn more about acceleration due to gravity here: brainly.com/question/88039

4 0

2 years ago

How would Newton's Three laws apply to a Ferris Wheel?

Cloud [144]

The Central pedal force of the wheels center is opposed by an equal force from the objects being spun around by the wheel

5 0

3 years ago

Which of the following would be used in luminosity calculations?

Daniel [21]

Answer:

1) joule

2) $kgm^{2}/s^{2}$

3) $10\%$

Explanation:

1) Luminosity is the <u>amount of light emitted</u> (measured in Joule) by an object in a unit of<u> time</u> (measured in seconds). Hence in SI units luminosity is expressed as joules per second ( $\frac{J}{s}$ ), which is equal to Watts ( $W$ ).

This amount of light emitted is also called radiated electromagnetic power, and when this is measured in relation with time, the result is also called radiant power emitted by a light-emitting object.

Therefore, if we want to calculate luminosity the Joule as a unit will be used.

2) Work $W$ is expressed as force $F$ multiplied by the distane $d$ :

$W=F.d$

Where force has units of $kgm/s^{2}$ and distance units of $m$ .

If we input the units we will have:

$W=(kgm/s^{2})(m)$

$W=kgm^{2}/s^{2}$ This is 1Joule ( $1 J$ ) in the SI system, which is also equal to $1 Nm$

3) The formula to calculate the percent error is:

$\% error=\frac{|V_{exp}-V_{acc}|}{V_{acc}} 100\%$

Where:

$V_{exp}=7.34 (10)^{-11} Nm^{2}/kg^{2}$ is the experimental value

$V_{acc}=6.67 (10)^{-11} Nm^{2}/kg^{2}$ is the accepted value

$\% error=\frac{|7.34 (10)^{-11} Nm^{2}/kg^{2}-6.67 (10)^{-11} Nm^{2}/kg^{2}|}{6.67 (10)^{-11} Nm^{2}/kg^{2}} 100\%$

$\% error=10.04\% \approx 10\%$ This is the percent error

8 0

3 years ago

Suppose we are given a square coil that is 5.5 cm on a side containing 100 loops of very fine wire. The total resistance of this

maw [93]

Answer:

I = 578A

Explanation:

The magnitude of the peak value of the induced current flowing in a coild is given by

$I = \frac{\epsilon_{max}}{R}$

$I = \frac{NBA\omega}{R}$

Where

I= current

N = Number of loops

$\omega =$ angular velocity

R= Resistance

B = Magnetic field

A = Area

Replacing our values we have that,

$I = \frac{(100)(1.3)(0.055)^2(2.5)}{1.7*10^{-3}}$

$I = 578A$

8 0

3 years ago

If a stereo has a dial that changes the volume of sounds the stereo makes what is the dial doing

vredina [299]

The volume dial is acting as a voltage divider or a variable resistor.

4 0

3 years ago

Read 2 more answers