Answer:
1, 1583.33 V/m
2, 4.72*10^-12 C
3, 39.2*10^-11 C
Explanation:
1
E = V / d
E = 8.55 / 5.4*10^-3
E = 8.55 / 0.0054
E = 1583.33 V/m
2
Capacitance, C = (k * e0 * A) / d, where k = 1
A = area of capacitor, 3.37 cm² = 3.37*10^-4 m²
d = plate separation, 5.4 mm
e0 = Constant, 8.85*10^-12
Applying these, we have
C = (1 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 29.82*10^-16 / 0.0054
C = 5.52*10^-13 F
Since Q = CV, then
Q = 5.52*10^-13 * 8.55
Q = 4.72*10^-12 C
3
We are given that k = 83, so
Capacitance, C = (k * e0 * A) / d
C = (83 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 2.475*10^-13 / 0.0054
C = 4.58*10^-11 F
Q = CV
Q = 4.58*10^-11 * 8.55
Q = 39.2*10^-11 C
Answer:
There are four main ways of doing that :-
- Velocity
- Acceleration
- Momentum
- Kinetic energy
Hope it helps!
Corrected question: The wavelength of light beam<u> </u><u>A</u> is twice the wavelength of light beam B. The energy of a photon in beam A is:
Answer:
B
Explanation:
Energy = hc/λ
λ(A) =2λ(B)...................equation 1
We will solve for the ratio of energy of A to energy of B.which is
=(hc/λA) ÷ (hc/λB)
referring to equation 1 we have
=(hc/2λB) ÷ (hc/λB)
=hc/2λB) × (λB/hc)
= λB/2λB
=1/2
The energy of A is half of B
