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3 years ago

How many electrons have been removed from a positively charged electroscope if it has a net charge of 6x10-11?

Physics

1 answer:

faltersainse [42]3 years ago

4 0

Answer:

<h3>Because one Coulomb of charge is an abnormally large quantity of charge, the units of microCoulombs (µC) or nanoCoulombs (nC) are more commonly used as the unit of measurement of charge. To illustrate the magnitude of 1 Coulomb, an object would need an excess of 6.25 x 1018 electrons to have a total charge of -1 C.</h3>

Explanation:

<h3><em><u>mark as brainliast</u></em></h3><h3><em><u>indian </u></em><em><u>genius </u></em><em><u>s</u></em><em><u>a</u></em><em><u>r</u></em><em><u>thak</u></em></h3>

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A 3874-kg rollercoaster is brought to the top of a 42m hill in 40 seconds,then drops 28m before the next hill.

Ede4ka [16]

(a) The work required to get the coaster to the top of the first hill is 1,594,538.4 J.

(b) The power required to bring the train to the top of the first hill is 39,863.46 W.

(d) The left at the bottom is determined as 1,063,025.6 J.

<h3>Work done to bring the rollercoaster top of the hill</h3>

W = Fn x d = mgh

W = 3874 x 9.8 x 42

W = 1,594,538.4 J

<h3>Power dissipated in bringing the rollercoaster on top hill</h3>

P = Fv

P = Fd/t

P = W/t

P = 1,594,538.4 /40 = 39,863.46 W

<h3>Energy lost when the coaster drops</h3>

E = 1,594,538.4 - (3874 x 9.8 x 28)

E = 531,512.8 J

<h3>Energy left at the bottom</h3>

E = 3874 x 9.8 x 28 = 1,063,025.6 J

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2 years ago

What is the amplitude of photo as they passed a black hole

aalyn [17]

Answer:

Explanation:

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2 years ago

You lift a 2.0 kg book from a shelf that is 1 m from the floor. What is the potential energy with respect to floor?

sladkih [1.3K]

Potential energy = mgh
Potential energy = 2 x 9.8 x 1
Potential energy 19.6 J

8 0

2 years ago

A science teacher gives a student four beakers, each with a different liquid inside. The table provided shows the volume of each

Ksivusya [100]

The dependent variable in this experiment is the mass of each liquid.

Density is the ratio of mass to volume of a substance. In this experiment, since the volume of each liquid is given, to get density, mass of each quantity must be known which is the outcome.

Density also depend on the mass of a substance and density can easily be identified by mass if all the substance in question have the same volume.

In this experiment, all the liquid have the same volume. Since the student want to list them in order from the least dense to the most dense, how dense the liquid are will be a function of the differences in liquid mass.

The least dense liquid will float. That is, will be at the top most of the container. While the most dense will be at the bottom of the container.

Therefore, the dependent variable in this experiment is the mass of each liquid

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7 0

2 years ago

Read 2 more answers

A small cork with an excess charge of +6.0µC is placed 0.12 m from another cork, which carries a charge of -4.3µC.

Volgvan

A) 16.1 N

The magnitude of the electric force between the corks is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

$q_1 = 6.0 \mu C=6.0 \cdot 10^{-6} C$ is the magnitude of the charge on the first cork

$q_2 = 4.3 \mu C = 4.3 \cdot 10^{-6}C$ is the magnitude of the charge of the second cork

r = 0.12 m is the separation between the two corks

Substituting numbers into the formula, we find

$F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(6.0\cdot 10^{-6}C)(4.3\cdot 10^{-6} C)}{(0.12 m)^2}=16.1 N$

B) Attractive

According to Coulomb's law, the direction of the electric force between two charged objects depends on the sign of the charge of the two objects.

In particular, we have:

- if the two objects have charges with same sign (e.g. positive-positive or negative-negative), the force is repulsive

- if the two objects have charges with opposite sign (e.g. positive-negative), the force is attractive

In this problem, we have

Cork 1 has a positive charge

Cork 2 has a negative charge

So, the force between them is attractive.

C) $2.69\cdot 10^{13}$

The net charge of the negative cork is

$q_2 = -4.3 \cdot 10^{-6}C$

We know that the charge of a single electron is

$e=-1.6\cdot 10^{-19}C$

The net charge on the negative cork is due to the presence of N excess electrons, so we can write

$q_2 = Ne$

and solving for N, we find the number of excess electrons:

$N=\frac{q_2}{e}=\frac{-4.3\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=2.69\cdot 10^{13}$

D) $3.75\cdot 10^{13}$

The net charge on the positive cork is

$q_1 = +6.0\cdot 10^{-6}C$

We know that the charge of a single electron is

$e=-1.6\cdot 10^{-19}C$

The net charge on the positive cork is due to the "absence" of N excess electrons, so we can write

$q_1 = -Ne$

and solving for N, we find the number of electrons lost by the cork:

$N=-\frac{q_1}{e}=-\frac{+6.0\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=3.75\cdot 10^{13}$

6 0

2 years ago