Answer with Explanation:
We are given that
Mass of spring,m=3 kg
Distance moved by object,d=0.6 m
Spring constant,k=210N/m
Height,h=1.5 m
a.Work done to compress the spring initially=
b.
By conservation law of energy
Initial energy of spring=Kinetic energy of object



v=5.02 m/s
c.Work done by friction on the incline,

It would be A: Have a greater height.
The higher the wave the higher the energy!
Answer:
16 m/s
Explanation:
Given that
y momentum = 0.080 *25 = 2
x momentum = 0.075*20 = 1.5
total momentum = √(4 + 2.25)
Total momentum = √6.25
Total momentum = 2.5
total mass = mass of x and y momentum = 0.075 + 0.080 = 0.155
speed of mass center = total momentum / total mass = 2.5/0.155 = 16.
And thus, the speed of the center of mass of this two-particle system at this instant is 16 m/s
Answer:
Though nepalgunj and taplegunj lie at the same latitude(28 degree) they greatly vary In climate..
Answer:
21.67 rad/s²
208.36538 N
Explanation:
= Final angular velocity = 
= Initial angular velocity = 78 rad/s
= Angular acceleration
= Angle of rotation
t = Time taken
r = Radius = 0.13
I = Moment of inertia = 1.25 kgm²
From equation of rotational motion

The magnitude of the angular deceleration of the cylinder is 21.67 rad/s²
Torque is given by

Frictional force is given by

The magnitude of the force of friction applied by the brake shoe is 208.36538 N