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3 years ago

How many electrons have been removed from a positively charged electroscope if it has a net charge of 6x10-11?

Physics

1 answer:

faltersainse [42]3 years ago

4 0

Answer:

<h3>Because one Coulomb of charge is an abnormally large quantity of charge, the units of microCoulombs (µC) or nanoCoulombs (nC) are more commonly used as the unit of measurement of charge. To illustrate the magnitude of 1 Coulomb, an object would need an excess of 6.25 x 1018 electrons to have a total charge of -1 C.</h3>

Explanation:

<h3>mark as brainliast</h3><h3>indian genius sarthak</h3>

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The mass of your new motorcycle is 250kg. What is the weight on the moon in newtons

Hunter-Best [27]

Weight of motorcycle on the moon = mg

Here, g= 1.622 m/s²

So, W = 250 * 1.622 = 405.5 Kgm/s² = 405.5 N.

Did you understand??

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3 years ago

How does Solar Energy impact the environment? Use in your own words.

lawyer [7]

Answer:

It helps to reduce polution and gasses that damage our good gases and the greenhouse gases. It produces energy from the sun. It is the cleanest way to go!

Explanation:

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3 years ago

Car A is traveling at a constant speed vA = 130 km / h at a location where the speed limit is 100 km / h. The police offi cer in

kotykmax [81]

Answer:

Distance = 713.303m

Explanation:

To determine the distance required for the police officer to overtake car A, we simply calculate the time t for which the police car and the speeding car have traveled equal distances from point P

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3 years ago

Read 2 more answers

An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing

exis [7]

Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane = 7.2 × 10³ kg

density of air = 1.29 kg/m³

using Bernoulli's equation

$P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2$

$\Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)$

$\Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)$

$\Delta P =9977.5 Pa$

Applying newtons second law

2 Δ P x A - mg = 0

$A =\dfrac{mg}{2\Delta P}$

$A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}$

A = 3.53 m²

7 0

3 years ago

A person on a diet loses 1.6 kg in a week. How many micrograms/second (µg/s) are lost?

Ivan

Based on the given values above, in order for us to get the answer, we need to convert the units first. So in 1 kilogram, there is 1,000,000 micrograms. In this case, 1.6 kilograms is 1,600,000 micrograms. For the week to seconds, 1 week is equivalent to 604,800 seconds. Therefore, 1,600,000 micrograms/604,800 seconds. So we are going to simplify this. So it would be 2.65µg/s. Hope this answers your question.

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3 years ago