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8090 [49]
3 years ago
13

The ionization energies (kJ/mol) of hydrogen, nitrogen, sodium, chlorine, and fluorine are 1,312, 1,402, 496, 1,256, and 1,681,

respectively. Which element is most likely to become a monoatomic ion with fluorine when these atoms interact?
Chemistry
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer: Sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

With increase in atomic size of the atom, there will be less force of attraction between the nucleus and the valence electrons of the atom. Hence, with lesser amount of energy the valence electrons can be removed.

More is the value of ionization energy more it is difficult to remove an electron. Therefore, lesser is the reactivity of element.

Hence, we can conclude that sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

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Answer:

false

Explanation:

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How many moles is 1.25 x 1024 atoms of bromine?
Irina-Kira [14]

Answer:

2.08 moles (3 s.f.)

Explanation:

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Answer:

See explanation

Explanation:

The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.

2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.

As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than  2-methylpropane.

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How many mols are in 100.g of Fe?
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Answer:

1.79 moles

Explanation:

1.79 moles

1.79 moles

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