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8090 [49]
3 years ago
13

The ionization energies (kJ/mol) of hydrogen, nitrogen, sodium, chlorine, and fluorine are 1,312, 1,402, 496, 1,256, and 1,681,

respectively. Which element is most likely to become a monoatomic ion with fluorine when these atoms interact?
Chemistry
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer: Sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

With increase in atomic size of the atom, there will be less force of attraction between the nucleus and the valence electrons of the atom. Hence, with lesser amount of energy the valence electrons can be removed.

More is the value of ionization energy more it is difficult to remove an electron. Therefore, lesser is the reactivity of element.

Hence, we can conclude that sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

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A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera
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T = 36.393\,^{\textdegree}C

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The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

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-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)

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-1.438\cdot T +78.227^{\textdegree}C = T - 10.5^{\textdegree}C

2.438\cdot T = 88.727\,^{\textdegree}C

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