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2 years ago

What is a vocab word for Friction?

1 answer:

7 0

Answer: Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

Explanation:

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What is another name for the nucleotides in DNA?

Gala2k [10]

Answer:

DNA is made up of four building blocks called nucleotides: adenine (A), thymine (T), guanine (G), and cytosine (C).

4 0

2 years ago

Electrolysis can be used for all of the following, except A. separating metals from ores. B. plating objects with metal coatings

Assoli18 [71]

The answer is D. recharging batteries.

3 0

3 years ago

A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t

VashaNatasha [74]

Answer: $V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=\frac{P_1V_1T_2}{T_1P_2}$

where,

$P_1$ = initial pressure of gas = 101.3 kPa

$P_2$ = final pressure of gas = 94.6 kPa

$V_1$ = initial volume of gas = 20.0 ml

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $297K$

$T_2$ = final temperature of gas = $283K$

Now put all the given values in the above equation, we get the final volume of gas.

$V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

$V_2=20.4ml$

Thus the correct numerical setup for calculating the new volume is $\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

3 0

3 years ago

Consider the following reaction:

adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

2H₂O₂ ⟶ 2H₂O + O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

d[H₂O]/dt = 2d[O₂]/dt = 2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = 6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂

(a) Initial moles of H₂O₂

$\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }$

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

$\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }$

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

$\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}$

8 0

3 years ago

What is the empirical formula for the following molecular formula: C10H5O2

Tju [1.3M]

The empirical formula is the same as the molecular formula : C₁₀H₅O₂

<h3>Further explanation</h3>

Given

Molecular formula : C₁₀H₅O₂

Required

The empirical formula

Solution

The empirical formula (EF) is the smallest comparison of atoms of compound forming elements.

The molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.

(empirical formula) n = molecular formula

(EF)n = C₁₀H₅O₂

If we divide by the number of moles of Oxygen (the smallest) which is 2 then the moles of Hydrogen will be a decimal number (not whole), which is 2.5, then the empirical formula is the same as the molecular formula

4 0

2 years ago