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3 years ago

What is the nuclear charge of a berrylium atom?

Chemistry

1 answer:

ICE Princess25 [194]3 years ago

4 0

Answer:

The charge on the nucleus of an atom; controlled by the number of protons and electrons present in an atom.

Explanation:

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How would you calculate the number of nanometers in 8.1 cm

devlian [24]

A: 8.1 • 10^7 nanometers

Because 1cm = 1 • 10^7 nm
So 8.1cm • (1 • 10^7 nm) = 8.1.10^7

4 0

4 years ago

Hydrogen gas and bromine gas react to form hydrogen bromide gas. How much heat (kJ) is released when 155 grams of HBr is formed

VashaNatasha [74]

Answer:

-37.63KJ

Explanation:

First, we write an equation of reaction:

H + Br ——-> HBr

Now we are told that 155g of HBr is formed. We can calculate the number of moles of HBr formed as follows:

We simply divide the mass of the HBr formed by the molar mass of HBr. The molar mass of HBr is 81g/mol

The number of moles of HBr formed is thus 81/155 = 0.52 moles

The amount of heat released is thus 0.52 * (-72) = -37.63KJ

8 0

3 years ago

What is a Fahrenheit??

Scrat [10]

Fahrenheit is a temperature scale

8 0

3 years ago

Read 2 more answers

Calculate the molar concentration of HA (90.2 g/mol) in a solution that has a specific gravity of 1.24 and is 64% HNO3 (w/w).

ser-zykov [4K]

Answer:

Explanation:

Hello,

In this case, considering the given specific gravity we are to compute the density of the 64% HNO3 solution:

$\rho=1.24*1g/mL=1.24g/mL$

In such a way, since the given solution of nitric acid is 64 % by mass, we've got:

$\frac{64gHNO_3}{100g\ solution}$

Thus, by using the previously computed density and the molar mass of HA (90.2 g/mol) we can compute the required molar concentration as follows:

$M=\frac{(100g-64g)HA}{100g\ solution}*\frac{1.24g\ solution }{1mL \ solution}*\frac{1000mL\ solution}{1L\ solution}*\frac{1molHA}{90.2gHA} \\\\M=4.95M$

Regards.

8 0

3 years ago

Arrange the following units in decreasing order: nm,km,pm,Dm,mm,m,cm,hm,gm

goblinko [34]

The units are nm (nano-meter), km (kilo-meter), pm (pico-meter), dm (decimeter), mm (millimeter), m (meter), cm (centimeter), hm (hectometer) and gm (gigameter). Now we can express each of these units in terms of m.

1 nm = $10^{-9}m$ , 1 Km = $10^{3}m$ 1 pm = $10^{-12}m$ , 1 dm = 0.1 m, 1 mm = 0.001 m, 1 cm = 0.01 m, 1 hm = 100 m, 1 gm = $10^{9} m$ . Thus the decreasing unit will be

gm>km>hm>m>dm>cm>mm>nm>pm

3 0

3 years ago