Solving Equation A
Given the equation A
and point (-3, 3)
The distance from the point (x₀, y₀) to the line Ax+By+C=0 is given by
To apply this formula, we first need to express the line in standard form
After substituting: A=4, B=-1, C=2, x₀=-3, y₀=3
units
Therefore, the distance between the line y = 4x - 2 and the point (-3, 3) will be:
Solving Equation B
Given the equation B
and point (-1, -2)
The distance from the point (x₀, y₀) to the line Ax+By+C=0 is given by
To apply this formula, we first need to express the line in standard form
After substituting: A=4, B=1, C=-5, x₀=-1, y₀=-2
units
Therefore, the distance between the line y = -x + 5 and the point (-1, -2) will be: