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Kay [80]
3 years ago
15

Help please

Chemistry
2 answers:
ss7ja [257]3 years ago
7 0
0.0821 L-atm/mol-K
8.314 kPa-L/mol-K
Delvig [45]3 years ago
7 0

Answer : The correct options are, (2) 8.314 kPa-L/mol-K and (4) 0.0821 L-atm/mol-K

Explanation :

As we know that the 'R' is the gas constant in the ideal gas law.

There are different values of gas constant 'R'. The values are,

8.314JK^{-1}mole^{-1}\\\\0.0821L\text{ atm }K^{-1}mole^{-1}\\\\0.08314L\text{ bar }K^{-1}mole^{-1}\\\\8.314K\text{ Pa }LK^{-1}mole^{-1}\\\\2calK^{-1}mole^{-1}

Hence, the correct options are, (2) 8.314K\text{ Pa }LK^{-1}mole^{-1} and (4) 0.0821L\text{ atm }K^{-1}mole^{-1}


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Acetic acid, ethanol, acetaldehyde and ethane form a series of 2-carbon molecules which differ in their extent of oxidation. Con
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Explanation:

Ethanol can be oxidized to ethanal or acetaldehyde which is further oxidized to acid that is acetic acid.

CH_3CH_2OH→  CH_3CHO [oxidation by loss of hydrogen]

  • An oxidizing agent potassium dichromate(VI) solution is used to remove the hydrogen from the ethanol.  
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Acetaldehyde can also be reduced back to ethanol again by adding hydrogen to it by using a reducing agent that is sodium tetrahydro borate, NaBH4.

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     CH_3CHO  →  CH_3CH_2COOH [reduction by the gain of electrons]

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Explanation: Reactivity of elements is defined as the tendency to loose or gain electrons.

These reactions are a type of single displacement reactions. A single displacement reaction is a type of reaction in which an element displaces another element in a chemical reaction. These are studied with the help of reactivity series.

The element which lies above in the reactivity series can easily displace the element which lies below in the reactivity series.

Option A: This reaction will not yield a stable product because Zinc lies below Aluminium in the reactivity series.

AlBr_3+Zn\rightarrow \text{No reaction}

Option B: This reaction will yield a stable product because Sodium lies above Calcium in the reactivity series.

CaBr_2+2Na\rightarrow 2NaBr+Ca

Option C: This reaction will not yield a stable product because Hydrogen lies below Magnesium in the reactivity series.

MgBr_2+H_2\rightarrow \text{No reaction}

Option D: This reaction will not yield a stable product because Calcium lies below Barium in the reactivity series.

BaBr_2+Ca\rightarrow \text{No reaction}

Option E: This reaction will not yield a stable product because barium lies below Lithium in the reactivity series.

2LiBr+Ba\rightarrow \text{No reaction}

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