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Answer:
7,38 g of K₃PO₄
Explanation:
Molarity is an unit of chemical concentration. 0,139 M means 0,139 moles of solute per liter of solution.
In this case, the solute is potassium phosphate (K₃PO₄; molar mass: 212,27 g/mol) and the volume of the solution must be 250mL≡0,25L.
Thus, the moles of potassium phosphate you need are:
0,139 mol/L×0,25L = 0,03475 moles of K₃PO₄
In grams:
0,03475 moles of K₃PO₄ × = 7,38 g of K₃PO₄
I hope it helps!
Answer:- Third choice is correct, 17.6 moles
Solution:- The given balanced equation is:
We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.
From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.
It is a simple mole to mole conversion problem. We solve it using dimensional set up as:
= 17.6 mol KOH
So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.