Answer:
In the first combination neutralization takes place to give a salt. So, solution 'a' is neutral in nature.
In the solution 'c', both salts are resulted by the combination of weak base and strong acid. The combination of these salts suppresses the acidity.
In last combination basic nature is observed due to the presence of CN⁻ ions. Thus, the solution 'd' is basic in nature.
Out of the five given solutions, 0.0100 M in HF and 0.0100 M in KBr is most acidic. Therefore, solution 'b' is most acidic in nature.
Explanation:
I believe that it most likely would be C,
M=f/a m=129000N/84m/s/s=1535.714286kg/m/s/s
Answer:
B
Explanation:
Molarity = 0.010M
Volume = 2.5L
Applying mole-concept,
0.010mole = 1L
X mole = 2.5L
X = (0.010 × 2.5) / 1
X = 0.025moles
0.025moles is present in 2.5L of NaOH solution.
Molar mass of NaOH = (23 + 16 + 1) = 40g/mol
Number of moles = mass / molar mass
Mass = number of moles × molar mass
Mass = 0.025 × 40
Mass = 1g
1g is present in 2.5L of NaOH solution
