Answer:
Explanation:
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In this case, according to the given information and chemical equation, it turns out possible for us to calculate the moles of C2O4^2- by firstly setting up the equilibrium expression:
![Kc=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[Fe^{3+}][C_2O_4^{2-}]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5B%5BFe%28C_2O_4%29_3%5D%5E%7B3-%7D%5D%7D%7B%5BFe%5E%7B3%2B%7D%5D%5BC_2O_4%5E%7B2-%7D%5D%5E3%7D)
However, according to the question, we just need to apply the given 1:3 mole ratio in the chemical reaction, of iron (III) ions to oxalate ions to obtain:
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Answer:
Here's what I find.
Explanation:
Many scientists contributed to our model of the atom.
Among those who received the Nobel Prize for their work are:
1906 — J.J. Thomson — discovery of the electron
1908 — Ernest Rutherford — nuclear model of the atom
1922 — Niels Bohr — planetary model of the atom
1922 — Albert Einstein — quantum mechanical model of the atom
1935 — James Chadwick — discovery of the neutron
Answer:
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<span> I got (a). The answer was 7.53. But when I try to solve (d), I keep getting the wrong answer. I subtracted the moles of NaOH from the acid and added the moles to the base. Then I did Ka = (x*([NaClO]+x))/([HClO - x) and then I found the pH</span>
Answer:
Theoretical yield of vanadium = 1.6 moles
Explanation:
Moles of 
= 1.0 moles
Moles of 
= 4.0 moles
According to the given reaction:-
1 mole of react with 5 moles of
Moles of Ca available = 4.0 moles
Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)
The formation of the product is governed by the limiting reagent. So,
5 moles of Ca on reaction forms 2 moles of V
1 mole of Ca on reaction for 2/5 mole of V
4.0 mole of Ca on reaction for 
mole of V
Moles of V = 1.6 moles
<u>Theoretical yield of vanadium = 1.6 moles</u>
