The inner planets are usually rocky because the gravitational pull is stronger closer to the star or in this case the sun. The dust and rocky particles that are left over after a super nova or in a nebula will tend to orbit closer to a proto-star when a solar system is in its early days. In our solar system these planets are Mercury, Venus, Earth and Mars. Gases are less dense and will be less affected by the pull of gravity because rocky particles have more mass. The outer planets are gas giants formed from clouds of gas that would be further out in the spinning disk around a proto-star.
because the car returned to A the velocity is 0
D. The velocity is zero but the speed
Yes, that's a reasonable rounded value for the solution.
(5.7)² + (5.8)² = (32.49) + (33.64) = 66.13
√66.13 = 8.132...
= 8.1 when rounded to the nearest tenth.
The solution ' 8.1 ' is a reasonable rounded value, but only
if the question is changed to say 'km' at every place where
it now says 'km/hr'.
If 'km/hr' is correct, then there's no way to calculate Kiley's
effective northwesterly speed, using only the given information.
We don't know how long she traveled north at 5.7 km/hr,
and we don't know how long she traveled west at 5.8 km/hr.
So we don't know the distance between her start and end
points, and we don't know how long she traveled altogether ...
exactly the two numbers we need in order to calculate her
average speed. Or even, for that matter, the average direction
of her trip from start to finish.
They would weight 69N on the moon's surface.
The formula for speed is v=dt
Where
v=velocity (speed with direction)
d=distance
t=time of displacement
