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Helga [31]
4 years ago
9

When does gravitational lensing occur? High concentrations of dark matter cause length contraction of nearby objects. The gravit

y from a distant object (like a quasar) distorts the appearance of nearby galaxies. Telescope lenses are distorted by gravitational forces from dark matter. A massive object (like a galaxy cluster) bends the light from an object (like a quasar) that lies behind it.
Physics
1 answer:
Stella [2.4K]4 years ago
4 0

Answer:

A massive object (like a galaxy cluster) bends the light from an object (like a quasar) that lies behind it.

Explanation:

A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.

This technique is useful for astronomers since they make research of faraway objects (at hight redshift) that otherwise will difficult to detect with a telescope.

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0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary for
Paladinen [302]

Assuming the accleration applied was constant, we have

v=v_0+at\implies v_0+20.0\,\dfrac{\mathrm m}{\mathrm s}=v_0+a(0.10\,\mathrm s)

\implies20.0\,\dfrac{\mathrm m}{\mathrm s}=a(0.10\,\mathrm s)

\implies a=200\,\dfrac{\mathrm m}{\mathrm s^2}

Then the force applied to the ball is given by

F=ma=(0.45\,\mathrm{kg})\left(200\,\dfrac{\mathrm m}{\mathrm s^2}\right)

\implies F=90\,\dfrac{\mathrm{kg}\,\mathrm m}{\mathrm s^2}=90.\,\mathrm N

8 0
3 years ago
Sound waves are all
elixir [45]

Answer:

transverse waves

Explanation:

sound waves are all transverse waves

8 0
3 years ago
What does the slope of the line on this velocity versus time graph represent?
maria [59]
What do you mean when you say "this" graph ?  I don't see any graph.

First of all, I'm sure you don't have a "velocity versus time" graph.
You may have a "speed versus time" graph, that doesn't show any
information about the direction of the motion.

As you look at your graph ... a feat that's impossible for me ... 

-- If the line is horizontal, then speed is not changing.  If the direction
of motion is also not changing, then there is zero acceleration.  Sadly,
the graph most likely doesn't carry any information about the direction. 
It's possible that the speed is constant but the direction is changing.
Then acceleration isn't zero, but you can't tell that from the graph.

-- If the line is proceeding upward from left to right, whether it's straight
or curving, then there is positive acceleration.

-- If the line is proceeding downward from left to right, whether it's straight
or curving, then there is negative acceleration, or what some people might
call "positive deceleration".

8 0
3 years ago
The half-life of Uranium is longer on Earth than the half-life of Uranium on the moon. True or False?
Nina [5.8K]
That's false.  The half-life of an unstable element
doesn't depend on its environment.
8 0
4 years ago
A 6.4 kg block with a speed of 5.4 m/s collides with a 12.8 kg block that has a speed of 3.6 m/s in the same direction. After th
jenyasd209 [6]

Answer:

The velocity of the 6.4 kg block immediately after the collision is 3.6 m/s in the original direction.

Explanation:

Given;

mass of first block, m₁ = 6.4 kg

initial speed of first block, u₁ =  5.4 m/s

mass of second block, m₂ = 12.8 kg

initial speed of second block, u₂ = 3.6 m/s

final speed of second block, v₂ = 4.5 m/s

To determine the final speed of 6.4 kg block immediately after the collision, we apply principle of conservation linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁  +  m₂u₂ = m₁v₁  + m₂v₂

where;

v₁ is the final speed of 6.4 kg block

v₂ is the final speed of 12.8 kg block

Substitute the given values of m₁, u₁, m₂,  u₂ , v₂ and calculate  v₁

6.4 x 5.4  +  12.8 x 3.6 = 6.4v₁  +  12.8 x 4.5

34.56 + 46.08  = 6.4v₁ + 57.6

80.64 = 6.4v₁  +  57.6

80.64 - 57.6 = 6.4v₁

23.04 = 6.4v₁

v₁ = 23.04 / 6.4

v₁  = 3.6 m/s

Therefore, the velocity of the 6.4 kg block immediately after the collision is 3.6 m/s in the original direction.

3 0
3 years ago
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