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mr_godi [17]
3 years ago
7

A 0.050 kg air track glider moving at 5.2 m/s hits a stationary 0.150 kg air track glider. Velcro makes them stick together afte

r impact. What is the common speed of the gliders?
Physics
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

1.3 m/sec

Explanation:

Mass of the first glider that is m_1=0.050\ kg

Velocity before hitting the second glider that is v_1 = 5.2m/sec

Mass of the second glider is that is m_2=0.150\ kg

After hitting the combined mass =m_1+m_2=0.050+0.150=0.200\ kg

We know that momentum is always conserved

So m_1v_1=(m_1+m_2)v_2

0.050\times 5.2=0.2\times v_2

v_2=1.3 m/sec

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Yes I’m going home I was finna was your birthday and I got to get my kids ready
4 0
3 years ago
Frank does 2400J of work in climbing a set of stairs. If he does the work in 6 seconds, what is his power output?
timurjin [86]
Power = Work Done / Time taken

         Where Work Done is Joules, and Time is in Seconds, Power is in Watts

            = 2400 J / 6 seconds

            = 400 Watts

The power output is 400 Watts.
4 0
3 years ago
What is the period of a pendulum that takes 3 seconds to move forward, and another 3 seconds to come back?
Serga [27]

The period of the pendulum is 6 seconds.

<h3>What is period?</h3>

Period is the time taken for a simple pendulum to move to(forward) and fro(backward). The s.i unit of period is seconds(s).

Note: When a simple pendulum moves to and fro. it completes one cycle.

From the question, The period of the pendulum is calculated using the formula below.

<h3>Formula</h3>
  • T = a+b.............. Equation 1

Where:

  • T = Period of the pendulum
  • a = Time taken for the pendulum to move forward
  • b = Time taken for the pendulum to move backward.

From the question,

Given:

  • a = 3 seconds
  • b = seconds

Substitute the values above into equation 1

  • T = 3+3
  • T = 6 seconds.

Hence, The period of the pendulum is 6 seconds.

Learn more about period here: brainly.com/question/21924087

5 0
3 years ago
Chris and Sue are wearing harnesses and are hanging from the ceiling by means of ropes attached to them. They are face to face a
Setler [38]

Answer:

h = 0.288m

Explanation:

Assume

v_1 = Speed of Sue

v_2 = Speed of Chris immediately after the push

Sue's KE = \frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65  

= 331.24

26v_{1}\ ^2 = 331.24

So, v_1 = 3.569

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

m_1v_1 = m_2v_2

52 \times 3.569  = 78 \times v_2

v_2 = 2.380

Chris kt = \frac{1}{2} \times 78 \times 2.380^2

= 220.827

220.827 = mgh

So, h = 0.288m

3 0
3 years ago
If the reading of a linear scale is 4 mm and no of division of the circular scale is 50, then what will be the diameter of the w
Sliva [168]

Answer:

Diameter of Wire = 4.5 mm

Explanation:

First, we need to find the fractional part of the reading. The fractional part o the reading can be given by the following formula:

Fractional Part = Circular Scale Reading x Least Count

where,

Circular Scale Reading = 50

Least Count = 0.01 mm

Therefore,

Fractional Part = (50)(0.01 mm)

Fractional Part = 0.5 mm

Now, the diameter of the wire can be given by using the following formula:

Diameter of Wire = Linear Scale Reading + Fractional Part

Diameter of Wire = 4 mm + 0.5 mm

<u>Diameter of Wire = 4.5 mm</u>

8 0
3 years ago
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