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mr_godi [17]
3 years ago
7

A 0.050 kg air track glider moving at 5.2 m/s hits a stationary 0.150 kg air track glider. Velcro makes them stick together afte

r impact. What is the common speed of the gliders?
Physics
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

1.3 m/sec

Explanation:

Mass of the first glider that is m_1=0.050\ kg

Velocity before hitting the second glider that is v_1 = 5.2m/sec

Mass of the second glider is that is m_2=0.150\ kg

After hitting the combined mass =m_1+m_2=0.050+0.150=0.200\ kg

We know that momentum is always conserved

So m_1v_1=(m_1+m_2)v_2

0.050\times 5.2=0.2\times v_2

v_2=1.3 m/sec

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DaniilM [7]
<em>Hello there, and thank you for asking your question here on brainly.

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3 0
4 years ago
Mohammad has been saving 8 each week. Today he spent 142 of the savings, and he now has 50 left. For how many weeks has he been
poizon [28]

Answer:

24 weeks

Explanation:

142+50=192

192/8=24

3 0
3 years ago
The maximum wavelength an electromagnetic wave can have and still eject an electron from a copper surface is 264 nm .What is the
Tamiku [17]

Answer:

4.71 eV

Explanation:

For an electromagnetic wave with wavelength

\lambda=264 nm = 2.64\cdot 10^{-7} m

the energy of the photons in the wave is given by

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.64\cdot 10^{-7}m}=7.53\cdot 10^{-19} J

where h is the Planck constant and c the speed of light. Therefore, this is the minimum energy that a photon should have in order to extract a photoelectron from the copper surface.

The work function of a metal is the minimum energy required by the incident light in order to extract photoelectrons from the metal's surface. Therefore, the work function corresponds to the energy we found previously. By converting it into electronvolts, we find:

E=\frac{7.53\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=4.71 eV

3 0
3 years ago
A speeding motorist traveling down a straight highway at 100 km/h passes a parked police car. It takes the police constable 1.0
Lubov Fominskaja [6]

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

<u>t = 7.5 s</u>

6 0
4 years ago
What is the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m?
notsponge [240]

Answer:

a ) 24 m/s

Explanation:

Given,

Frequency ( f ) = 6 Hz

Wavelength ( λ ) = 4 m

To find : Speed ( v ) = ?

Formula : -

v = f x λ

v

= 4 x 6

= 24 m/s

Therefore, the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m

is 24 m/s.

4 0
3 years ago
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