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Hope it helps!
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Answer:
What will be the increase in frequency if these waves are reflected = 2979.63Hz
Explanation:
The detailed steps and appropriate formula is as shown in the attached file.
Answer:
The energy of the photon from the higher-wattage bulb is equal to the energy of the photon from the lower-wattage bulb.
Explanation:
Answer:
both charges will have different potential energies that will depend upon the charge magnitude.
Explanation:
It is given that both the charges are on the same equipotential line which means the potential V at which the two charges are is same.
Now the potential energy of a charge at potential V is given by
q×V where q is the charge value
Thus Higher the charge value for a given value of potential , higher will be the potential energy
Thus the larger charge will have higher potential energy and not the same.
