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3 years ago

The difference in the composition of the terrestrial planets and the gas giants can be explained by the different condensation

1 answer:

6 0

The inner planets are usually rocky because the gravitational pull is stronger closer to the star or in this case the sun. The dust and rocky particles that are left over after a super nova or in a nebula will tend to orbit closer to a proto-star when a solar system is in its early days. In our solar system these planets are Mercury, Venus, Earth and Mars. Gases are less dense and will be less affected by the pull of gravity because rocky particles have more mass. The outer planets are gas giants formed from clouds of gas that would be further out in the spinning disk around a proto-star.

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A Each time he does one pushup, Jose, who has a mass of 89kg, raises his center of mass by 25 cm. He completes an impressive set

k0ka [10]

The Metabolic power,If we assume that lowering his body has no energetic cost is 667 J/min

The Metabolic power, If lowering of his body needs half of the energy is 1000J/min

Explanation:

1.If we assume that lowering his body has no energetic cost:

Metabolic energy in 5 minutes

= Increase in potential energy for 150 pushups

= (89 kg) × (25/100 m) × 150

= 3337.5 J

Metabolic power

= (3375.5 J) / (5 min)

= 667 J/min

The Metabolic power,If we assume that lowering his body has no energetic cost is 667 J/min

2.If lowering of his body needs half of the energy what it costs to raise it.

Metabolic power

= (667 J/min) × [1 + (1/2)]

= 1000 J/min

The Metabolic power, If lowering of his body needs half of the energy is 1000J/min

5 0

3 years ago

A 2.40 μC charge is subject to a 3.00 mN force due to an Electric Field. What is the magnitude of the Electric Field at the loca

Bezzdna [24]

<h2>Electric field at the location of the charge is 1250 N/C</h2>

Explanation:

Electric field is the ratio of force and charge.

Force, F = 3.00 mN = 3 x 10⁻³ N

Charge, q = 2.40 μC = 2.40 x 10⁻⁶ C

We have

$E=\frac{F}{q}\\\\E=\frac{3\times 10^{-3}}{2.40\times 10^{-6}}\\\\E=1250N/C$

Electric field at the location of the charge is 1250 N/C

4 0

3 years ago

For an object like a planet, with a typical temperature of a few hundred kelvin, what kind of blackbody radiation would it princ

navik [9.2K]

Answer:

Low-temperature blackbody

Explanation:

There are 3 types of blackbody temperatures.

Low-temperature blackbody

High temperature extended area blackbody

High-temperature cavity blackbody

A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.

6 0

3 years ago

A waist-to-hip ratio of 1.0 is considered healthy. True False

laila [671]

false a waist to hip ratio that is healthy would be .80 or less is considered healthy for most individuals hope this helps

7 0

3 years ago

Read 2 more answers

14)

Mama L [17]

Watt is a unit for power that is also equal to J/s. We therefore need to convert the minutes to seconds first before answering. Every minute is comprised of 60 seconds. Therefore, 3 minutes are composed of 180 seconds. Multiplying the number of seconds to the given power will give us,
Work = Power x time
= (1500 J/s) x (180 s)
= 270,000 J
Therefore, the answer is letter D.

6 0

3 years ago