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elena-14-01-66 [18.8K]
3 years ago
15

Is starch a simple sugar molecule?​

Biology
2 answers:
natta225 [31]3 years ago
4 0

Answer:

Simple vs Complex Carbs. Carbohydrates are sugars that come in 2 main forms – simple and complex. This is also referred to as simple sugars and starches. The difference between a simple and complex carb is in how quickly it is digested and absorbed – as well as it's chemical structure

Anon25 [30]3 years ago
3 0

Answer:

yes because Most carbohydrates can be broken down by digestion into glucose and these are the carbohydrates

Explanation:

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How much electrons would an atom of 10 protons and 11 neutrons have?
Elina [12.6K]

Answer:

10 electrons

Explanation:

Normally you would assume the atom to be neutral, meaning the protons and electrons cancel each other, if nothing states the charge of the atom. So, there must be 10 electrons in order to cancel out the protons.

Hope this helped :]

4 0
2 years ago
​specific topics that should be included as components of stage 1 obesity treatment include _____.
prohojiy [21]

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5 0
3 years ago
In a genotype such as Bb, what does each letter represent?
-Dominant- [34]

I believe the capital b (B) is refered to as the dominant gene and the lower case b (b) is refered to as the subordinate/recessive gene.

4 0
3 years ago
James wants to create a self-sustaining ecosystem, or vivarium. Which method would most likely result in an ecosystem that is vi
KiRa [710]
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6 0
3 years ago
Read 2 more answers
A population of horses has individuals that are either gray or chestnut colored. The gray color allele, G, is dominant over the
Dahasolnce [82]

We solve the problem using the Hardy-Wineberg equation.

We have the frequency for gray trait as p =  = 0.8

∴ p² = 0.64

64 % of the horses are homozygous for the gray trait.

Solving for the frequency of white chestnut trait by using the fact that,

p + q = 1

∴ q = 1 - p = 1 - 0.8 = 0.2

Now we can calculate 2pq in p² + 2pq + q², which is the frequency for heterozygous gray trait,

∴ 2pq = 2 x 0.8 x 0.2 = 0.32

Therefore, in a population of 100 horses, 32% are heterozygous for gray trait.

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32 (heterozygous gray horses) + 64 (homozygous gray horses) = 96 (gray horses)

Hence, 96% of the horses are gray in color.

6 0
3 years ago
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