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uranmaximum [27]
2 years ago
9

I need help with my math

Mathematics
1 answer:
Brrunno [24]2 years ago
4 0

Answer:

<em><u>42</u></em>

Step-by-step explanation:

If you add 42+42+24+24= 132. If they are similar, then the other shape should be equal. So, 35+35+10+10= 90. Then you subtract 132-90= 42. So 42 is the missing amount that needs to be added to x.

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Write the equation in standard form of a line that is parallel to the graph of 2x + y = 5 and whose y - intercept is (0,4).
babunello [35]

The line that is parallel to this line will have the same slope of this line, as the two will never intersect. They will run side by side. The line y = 2x - 5 is written in slope-intercept form, which is y = mx + b. The value of m represents the slope, and in this equation m = 2. Therefore, the line we are looking for will have a slope of 2 also.

That line should also be in slope-intercept form. We now know the value of m, but we also know the value of x and y. The ordered pair (8, 10) is a point on the line, and every ordered pair is in the form (x, y). Therefore, x = 8 and y = 10. We can plug those values into y = mx + b, along with m = 2. That gives us:

10 = 2(8) + b We need to solve for b.

10 = 16 + b

b = -6

5 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH THIS!! ILL GIVE YOU BRAINLIST ANSWER <br> IMAGE DOWN BELOW!
Basile [38]

how long is |MN| when you measure it and do you know anything about the length of |NO| and |OP|?

assuming |MN|= 7.7 ; |NO|= 4.7 ; |MO|= 5.5:

o²= m²+n²

= 4.7²+5.5²

=52.34

o=V52.34

≈7.23

5 0
2 years ago
Which best describes the linear association shown in the scatter plot?
madam [21]
C strong negative is the answer
7 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
Help me please ....................................
atroni [7]

Answer:

I can't help u with this cause I do not know this kind of math I only learn about Fractions and other math except for algebra.

Step-by-step explanation:

I wish u the best of luck on trying to figure out this answer.

7 0
2 years ago
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