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3 years ago

Which answer choice lists the number and type of elements in a compound in the way that is close to their actual arrangement?

1 answer:

alexandr1967 [171]3 years ago

6 0

The chemical formula of a compound express the atoms by which the molecule is formed and the ratio of the atoms in which they are combined.

The space filling model of a compound describe the electron density in the compound of each atom.

The ball and stick arrangement of a compound describe the way in which the molecules are present in three dimensions.

The structural formula state the number of atoms present in the molecule, the type of element or atom present in the molecule and the way in which they are arranged closely which is the bond.

Thus only the structural formula only will cover all the options as stated.

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A teacher makes the following statement.

DedPeter [7]

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3 years ago

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What is the molarity of a solution of 3.0 mol of KCl in 4.0L of water?

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Answer:

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3 years ago

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3 years ago

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3 years ago

Calculate the pH of 1.00 L of the buffer 0.95 M CH3COONa/0.92 M CH3COOH before and after the addition of the following species.

natima [27]

Answer: (a) pH = 4.774, (b) pH = 4.811 and (c) pH = 4.681

Explanation: (a) pH of the buffer solution is calculated using Handerson equation:

$pH=pKa+log(\frac{base}{acid})$

pKa for acetic acid is 4.76. concentration of base and acid are given as 0.95M and 0.92M. Let's plug in the values in the equation and calculate the pH of starting buffer.

$pH=4.76+log(\frac{0.95}{0.92})$

pH = 4.76 + 0.014

pH = 4.774

(b) When 0.040 mol of NaOH (strong base) are added to the buffer then it reacts with 0.040 mol of acetic acid and form 0.040 mol of sodium acetate.

Original buffer volume is 1.00 L. So, the original moles of sodium acetate will be 0.95 and acetic acid will be 0.92.

moles of acetic acid after addition of NaOH = 0.92 - 0.040 = 0.88

moles of sodium acetate after addition of NaOH = 0.95 + 0.040 = 0.99

Let's again plug in the values in the Handerson equation:

$pH=4.76+log(\frac{0.99}{0.88})$

pH = 4.76 + 0.051

pH = 4.811

(c) When 0.100 mol of HCl are added then it reacts with exactly 0.100 moles of sodium acetate(base) and form 0.100 moles of acetic acid(acid).

so, new moles of acetic acid = 0.92 + 0.100 = 1.02

new moles of sodium acetate = 0.95 - 0.100 = 0.85

Let's plug in the values in the equation:

$pH=4.76+log(\frac{0.85}{1.02})$

pH = 4.76 - 0.079

pH = 4.681

5 0

4 years ago