Starting from the radon mass, add the mass of the electron, and subtract the mass attributable to the gamma radiation <u>(931 Mev = 1 amu).</u>
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<h3>
What is gamma radiation?</h3>
Gamma radiation (gamma rays) refers to the part of the electromagnetic spectrum with the most energy and shortest wavelength. Astrophysicists define gamma radiation as any radiation with an energy above 100 keV. Physicists define gamma radiation as high-energy photons released by nuclear decay.
Using the broader definition of gamma radiation, gamma rays are released by sources including gamma decay, lightning, solar flares, matter-antimatter annihilation, the interaction between cosmic rays and matter, and many astronomical sources. Gamma radiation was discovered by Paul Villard in 1900.
Gamma radiation is used to study the universe, treat gemstones, scan containers, sterilize foods and equipment, diagnose medical conditions, and treat some forms of cancer.
Learn more about gamma radiation
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Answer:the CO2 molecule has an excess of electron
Answer:
Q = 1360.248 j
Explanation:
Given data:
Mass of brass = 298.3 g
Initial temperature = 30.0°C
Final temperature = 150°C
Specific heat capacity of brass = 0.038 J/g.°C
Heat absorbed = ?
SOLUTION:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30.0°C
ΔT = 120°C
Q = 298.3 g × 0.038 J/g.°C × 120°C
Q = 1360.248 j
Answer:
23.34 %.
Explanation:
- The percentage of water must be calculated as a mass percent.
- We need to find the mass of water, and the total mass in one mole of the compound. For that we need to use the atomic masses of each element and take in consideration the number of atoms of each element in the formula unit.
- <em>Atomic masses of the elements:</em>
Cd: 112.411 g/mol, N: 14.0067 g/mol, O: 15.999 g/mol, and H: 1.008 g/mol.
- <em>Mass of the formula unit:</em>
Cd(NO₃)₂•4H₂O
mass of the formula unit = (At. mass of Cd) + 2(At. mass of N) + 10(At. mass of O) + 8(At. mass of H) = (112.411 g/mol) + 2(14.0067 g/mol) + 10(15.999 g/mol) + 8(1.008 g/mol) = 308.5 g/mol.
- <em> Mass of water in the formula unit:</em>
<em>mass of water</em> = (4 × 2 × 1.008 g/mol) + (4 × 15.999 g/mol) = 72.0 g/mol.
- <em>So, the percent of water in the compound = [mass of water / mass of the formula unit] × 100 = [(72.0 g/mol)/(308.5 g/mol)] × 100 = 23.34 %</em>
