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Korolek [52]
3 years ago
10

Ways to manage non-biodegradable waste​

Chemistry
1 answer:
Lisa [10]3 years ago
7 0

Answer:

The following are some ways of safely disposing of non-biodegradable waste.

1. Take them to a local recycling facility. Separate metal, plastic, glass, and other non-biodegradable waste and store them ready for recycling.

2. Combustion and energy recovery.

3. Disposal at sanitary facilities.

4. Reduce.

5. Landfills.

Explanation: Hope it helps! ^_^"

(G00gle)

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Will mark brainly read it make sense no funny business
Korolek [52]

Answer:  mixed

compound

Explanation:

6 0
3 years ago
A container is filled with a mixture of gases:
strojnjashka [21]

Answer:

The partial pressure of chlorine gas in the mixture is 1.55 atm.

Explanation:

Partial pressure of oxygen gas = p_1=1.0 atm

Partial pressure of nitrogen gas = p_2=0.75 atm

Partial pressure of chlorine gas = p_3=?

Total pressure of the mixture of gases = P = 3.30 atm

Using Dalton's law of partial pressure:

P=p_1+p_2+p_3

3.30 atm=1.0 atm+ 0.75 atm+p_3

p_3=3.30atm - (1.0 atm+ 0.75 atm)=1.55 atm

The partial pressure of chlorine gas in the mixture is 1.55 atm.

8 0
3 years ago
4. Arrange the following substances in order of increasing boiling point: CH3CH2OH, HOCH2CH2OH, CH3CH2Cl , and ClCH2CH2OH A. CH3
Studentka2010 [4]

Answer: Option (B) is the correct answer.

Explanation:

A molecules that will have more number of hydrogen bonding will has highest boiling point because to break the hydrogen bonds high heat needs to be provided.

So, in the molecule HOCH_{2}CH_{2}OH there is presence of two alcoholic groups. Hence, it will have strongest hydrogen bonding as compared to the rest of molecules.

In the molecule ClCH_{2}CH_{2}OH there will be hydrogen bonding and dipole-dipole interactions. Hence, it boiling point will be slightly less than HOCH_{2}CH_{2}OH.

In the molecule CH_{3}CH_{2}OH, there will be only hydrogen bonding. Hence, its boiling point is less than ClCH_{2}CH_{2}OH.

In the molecule CH_{3}CH_{2}Cl, there is no hydrogen bonding but there will be only dipole-dipole interactions. Hence, its boiling point will be the least.

Therefore, we can conclude that increasing order of boiling point will be as follows.

        CH_{3}CH_{2}Cl < CH_{3}CH_{2}OH < ClCH_{2}CH_{2}OH < HOCH_{2}CH_{2}OH

6 0
3 years ago
Write the formuler of the following organic compounds
Lana71 [14]

Answer:

All I know is these things hope they help u.

4 0
2 years ago
An important reaction in the formation of photochemical smog is the photodissociation of NO2: NO2 + hv &gt;&gt;&gt; NO(g) + O(g)
vaieri [72.5K]

Explanation:

NO_2 + hv\rightarrow NO(g) + O(g)

The maximum wavelength of light that can cause this reaction is 420 nm.

a) The wavelength given lies in the range of visible light range that is from 400 nano meters to 700 nano meters.

The light with wavelength of 420 nm is found in the range of visible light.

b)The maximum strength of a bond :

E=\frac{h\times c}{\lambda}

where,

E = energy of photon = Energy required to break single molecule of nitrogen dioxide

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 420 nm=420\times 10^{-9}m

E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8 m/s}{420\times 10^{-9}m}

E=4.733\times 10^{-19} J

Energy required to break 1 mole of nitrogen dioxide molecules:

= E\times N_A=4.733\times 10^{-19} J\times 6.022\times 10^{23} mol^{-1}

=285,012.66 J/mol=285.13 kJ/mol

(1 J = 0.001 kJ )

285.13 is the maximum strength of a bond, in kJ/mol, that can be broken by absorption of a photon of 420-nm light.

c) the photodissociation reaction showing Lewis-dot structures is given in an image attached.

6 0
3 years ago
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