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Brums [2.3K]
3 years ago
12

1.0 mole of KCl(aq) is added to which solution to produce a precipitate?

Chemistry
1 answer:
taurus [48]3 years ago
7 0

Answer:

Ag+

Explanation:

If you imagine as if the problem were double replacement, you would pair the Cl with one of the following ions provided in the choices. As seen on Table F, Ag+ paired with Cl- produces an insoluble compound, hence the precipitate. All the other ions shown in the multiple choice section, when paired with Cl- will produce a soluble compound, as a result NOT a precipitate.

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copper hydroxide and potassium sulfate are produced when potassium hydroxide reacts with copper sulfate balanced equation
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This problem is requiring the balanced chemical equation that takes place when copper hydroxide and potassium sulfate are produced when reacting potassium hydroxide with copper sulfate.

<h3>Balancing chemical equations:</h3>

In chemistry, balancing chemical equations is based on the law of conservation of mass, which demands us to have equal number of atoms on both sides of the chemical equation. This can be accomplished by inserting coefficients in front of the chemical species.

For this particular case, we have potassium hydroxide with copper sulfate on the reactants side, however, copper can be copper (I) or copper (II) as it has 1+ and 2+ as its possible oxidation numbers. In addition, copper hydroxide and potassium sulfate as the products. Hence, we can assume this is all about copper (II) so we can write:

KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

As we can see, potassium, hydrogen and oxygen have two atoms each on the products side, but just one on the reactants side; drawback we can overcome by putting a 2 in front of KOH so as to balance it:

2KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

Learn more about balancing chemical equations: brainly.com/question/8062886

8 0
2 years ago
Determine the amount of heat (in kj) required to vaporize 1.55 kg of water at its boiling point. for water, δhvap
Usimov [2.4K]
Heat required to vaporize 1 mol of water from water at 100C to steam at 100C = 40.7 kJ 
<span>1 mol of water weighs =  18.015g
</span>1.55 kg = <span>1550/18.015 mol = 86.03 mol 

</span><span>Heat required to vaporize :
</span>= 86.03 mol  x <span>40.7 kJ 
</span>
= 3501.421 kJ
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