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Soloha48 [4]
3 years ago
8

How to solve this!! plz , i have an exam tommorow

Chemistry
2 answers:
Soloha48 [4]3 years ago
5 0
 Was .08 off its 4.08 like that guy explained 


Serjik [45]3 years ago
3 0
First change the grams to moles using the molar mass of the compound which can be calculated by adding the mass of each atom from the periodic table.

the use mole-mole ration from the given reaction equation. then convert the moles to mass back again using the molar mass of that compound.

molar mass NaF= 42.0 g/ mol
molar mass MgF2= 62.3 g/ mol

moles NaF= 5.5 / 42.0 g= 0.131 mol NaF

2 moles NaF = 1 mole MgF2

so 0.131 mol NaF/ 2= 0.0655 mole MgF2

grams MgF2= 0.0655 moles x 62.3= 4.08 grams

or simplified

5.5 g NaF (1 mol NaF/ 42.0 g) (1 mol MgF2/ 2 mol NaF) (62.3 g/ 1 mol MgF2)= 4.08 grams 
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3Zn + 8HNO₃⇒ 3Zn(NO₃)₂ + 2NO + 4H₂O

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  
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Reaction

Zn + HNO₃⇒ Zn(NO₃)₂ + NO + H₂O

  • 1. gives a coefficient

aZn + bHNO₃⇒ Zn(NO₃)₂ + cNO + dH₂O

  • 2. make an equation

Zn : left = a, right =1 ⇒a=1

H : left = b, right = 2d⇒ b=2d (eq 1)

N : left = b, right = 2+c⇒b=2+c (eq 2)

O : left = 3b, right = 6+c+d ⇒3b=6+c+d(eq 3)

  • From eq 1 and eq 3

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6d=6+c+d

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  • From eq 2 and eq 3

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  • From eq 4 and eq 5

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10c=6+c

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c = 2/3

  • input eq 5

d = 2 x 2/3

d = 4/3

  • input eq 1

b = 2 x 4/3

b = 8/3

The equation

aZn + bHNO₃⇒ Zn(NO₃)₂ + cNO + dH₂O to

Zn + 8/3HNO₃⇒ Zn(NO₃)₂ + 2/3NO + 4/3H₂O x 3

3Zn + 8HNO₃⇒ 3Zn(NO₃)₂ + 2NO + 4H₂O

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