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goblinko [34]
3 years ago
8

Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s

table than those of the other halogens. Bonding theory, however, does allow one to propose structures for these acids and use formal charges for the evaluation of these structures. For a molecule of fluorous acid, the atoms are arranged as HOFO. (Note: In this oxyacid, the placement of fluorine is an exception to the rule of putting the more electronegative atom in a terminal position.) What is the formal charge on each of the atoms? Enter the formal charges in the same order as the atoms are listed.
Chemistry
1 answer:
steposvetlana [31]3 years ago
4 0
We are told we have an oxyacid of the formula HOFO. We will assume the atoms are in this order and will draw a proper lewis structure for this compound by first drawing bonds between each of the 4 atoms and then place the remaining electron pairs on each atom:
      ..    ..    ..
H - O - F - O:
      ··   ··    ··
We can calculate the formal charge of an atom using the following formula:

Formal charge = [# of valence electrons] - [# of non-bonded electrons + # of bonds]

H: Formal charge = [1]-[0+1] = 0

O: Formal charge = [6]-[4+2] = 0

F: Formal charge = [7]-[4+2] = +1

O: Formal charge = [6]-[6+1] = -1

As we can see the overall charge of the molecule is neutral since the fluorine as a +1 charge and the oxygen a -1 charge.
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This dipeptide is designated as: there is a structure for h3nchcnhchco with ch2oh group attached to the first (from left to righ
oksian1 [2.3K]

A dipeptide is formed when 2 amino acids are joined together by a peptide linkage.

Each amino acid molecule contains an amino group ( -NH₂) and a carboxyl ( -COOH) group. During peptide formation, a carboxyl group of one amino acid reacts with amino group of the other , resulting in the formation of a linkage known as "peptide linkage". A water molecule is also eliminated in this reaction.

A general peptide formation reaction can be written as

NH_{2}-CH_{2}-COOH + H_{2}N-CH_{2}-COOH \rightarrow NH_{2}-CH_{2}-CONH-CH_{2}-COOH +H_{2}O

In the above reaction, we can see a peptide linkage ( -CONH-) getting formed between 2 amino acid molecules.

In the given molecule the peptide linkage is shown by drawing a box around it. Please refer to the attached image.

If we want to know the amino acid molecules from which this peptide is formed, we will simply break the CO-NH bond.

We will add -OH group to CO part and -H to NH part to get 2 amino acid molecules as shown in the picture.

The two amino acids thus formed are Serine & Cysteine.

Serine is designated as "Ser" and Cysteine is designated as "Cys"

Therefore the given dipeptide is designated as "Ser-Cys"

4 0
3 years ago
If you have 10.0 grams of citric acid with enough baking soda (nahco3 how many moles of carbon dioxide can you produce?
kap26 [50]
Easy stoichiometry conversion :)

So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.

So, our first step would look like this:

10.0
------
  1

Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.

So, our 2nd step would look like this:

1 mole CO2
-----------------
84.007g NaHCO3

When we put it together: our complete stoichiometry problem would look like this:

10.0g NaHCO3     1mol CO2
---------------------- x -------------------------
            1                  84.007g NaHCO3

Now to find our answer, all we need to do is:
Multiply the two top numbers together (which is 10.0)
Multiply the two bottom numbers together (Which is 84.007)

And then....

Divide the top answer by the bottom answer.

10.0/84.007 is 0.119

So, from 10.0 grams of citric acid, we have 0.119 moles of CO2.

Hope I could help!
6 0
3 years ago
Read 2 more answers
Assuming you have 6.24 x 1014 electrons and the surface area of the pail is 0.2 m2, what is the charge density (C/m2)?
pentagon [3]

Answer:

σ = 4.998 E-4 C/m²

Explanation:

  • 1 Coulomb (C) ≡ 6.241509 E18 electrons (e)

∴ # elect = 6.24 E14 elect

charge (Q):

⇒ Q = (6.24 E14 elect)/( 1 C /6.241509 E18 elect) = 9.998 E-5 C

charge density (σ):

  • σ = Q/S

∴ surface area (S) = 0.2 m²

⇒ σ = ( 9.998 E-5 C ) / ( 0.2 m²)

⇒ σ = 4.998 E-4 C/m²

4 0
3 years ago
A scientist would most likely need to update her model when it
Marizza181 [45]
A scientist would most likely need to update her model when it no longer supports the latest results.
5 0
3 years ago
Read 2 more answers
What is plasma in chemistry​
faltersainse [42]

Explanation:

Plasma is an ionized gas, a distinct fourth state of matter. “Ionized” means that at least one electron is not bound to an atom or molecule, converting the atoms or molecules into positively charged ions.but plasma is present in human body too in a liquid form.

hope this helps you

have a nice day

8 0
2 years ago
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