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Leona [35]
3 years ago
5

When you push a 1.90-kg book resting on a tabletop, you have to exert a force of 2.10 N to start the book sliding. Once it is sl

iding, however, you can use a force of only 1.06 N to keep the book moving with constant speed. Part A What is the coefficient of static friction between the book and the tabletop?
Physics
1 answer:
zimovet [89]3 years ago
3 0
Static frictional force = ƒs = (Cs) • (Fɴ)
              2.26 = (Cs) • m • g
              2.26 = (Cs) • (1.85) • (9.8)
           Cs = 0.125 
kinetic frictional force = ƒκ = (Cκ) • (Fɴ)
              1.49 = (Cκ) • m • g
              1.49 = (Cκ) • (1.85) • (9.8)
           Cκ = 0.0822 
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You cause a particle to move from point A, where the electric potential is 11.3 V, to point B, where the electric potential is −
BabaBlast [244]

Explanation:

The electric potential is the electric potential energy per unit of charge

V=\frac{U}{q}

Using this definition, we can calculate the electrostatic potential energy change between point A and B:

\Delta U=U_A-U_B\\\Delta U=qV_A-qV_B\\\Delta U=q(V_A-V_B)

Electron: q=-1.6*10^{-19}C

\Delta U=-1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=-5.952*10^{-18}J

Proton: q=1.6*10^{-19}C

\Delta U=1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=5.952*10^{-18}J

Neutral hydrogen atom: q=0

\Delta U=0

Singly ionized helium atom: q=1.6*10^{-19}C

\Delta U=1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=5.952*10^{-18}J

8 0
4 years ago
I need help with these questions :<br>(see image )​
dem82 [27]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>

Height of Aeroplane = 500 meters

Speed of Aeroplane = 200 m/s

Acceleration due to gravity = g = 10m/s^2

time of package to reach the ground = t = ?

Horizontal distance = d = ?

<h2>_____________________________________</h2><h3>SOLUTION:</h3>

When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the plane as the plane is just moving in horizontal direction. So the bomb fall and will travel forward.

Initial horizontal velocity is given by,

                                            V_{ix} = 200 ms{-1}

Initial vertical velocity is given by,

                                            V_{iy} = 0m/s

By the second equation of motion under gravity,

                                           H = V_{iy}t + \frac{1}{2}gt^2\\\\500 = (0)t + \frac{1}{2}x10xt^2 \\\\500 = 0 + 5t^2\\\\t^2 = \frac{500}{5}\\\\t^2 = 100\\\\t = 10 seconds

<h2>_____________________________________</h2>

<u>For horizontal distance(d)</u>:

Horizontal distance has no acceleration thus d is given by

                                          d = vt

                                          d = 200x10

                                          d = 2000 meters

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

                 

4 0
3 years ago
A pickup truck is carrying a toolbox, but the rear gate of the truck is missing, so the box will slide out if it is set moving.
Anon25 [30]

Answer:

t=7.33 s

Explanation:

According to Newton's second law:

\sum F=m*a

because we don't want the box to slide, the acceleration has to be zero.

\sum F=-F_{friction}+F_{truck}=0\\F_{truck}=F_{friction}\\F_{friction}=\µ*m*g=0.500*9.81*m\\F_{friction}=4.91*m

we know that:

F=m*a\\4.91m=m*a\\a=4.91m/s^2

Now having the acceleration, we can use the following formula.

v_f=a*t\\t=\frac{36.0m/s}{4.91m/s^2}\\\\t=7.33s

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3 years ago
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photoshop1234 [79]
You get circular motion, where the acceleration is pointing towards the center of the circle, as long as they are constant, and not fluctuating.
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3 years ago
Which ion channels mediate the falling phase of an action potontial?
White raven [17]

Answer:

Voltage-gated K+ channels

4 0
3 years ago
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