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sashaice [31]
3 years ago
9

What is a middle c site

Physics
1 answer:
svet-max [94.6K]3 years ago
5 0

Middle C is the name given to the musical note C which is in the middle of the piano keyboard. The Middle C sits on a ledger line (an extension of the stave written just for one note).

I hope this helps -brycefoster

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You will begin with a relatively standard calculation.Consider a concave spherical mirror with a radius of curvature equal to 60
Strike441 [17]

a) 30.0 cm

For any mirror, the radius of curvature is twice the focal length:

r = 2f

where

r is the radius of curvature

f is the focal length

For the mirror in this problem, we have

r = 60.0 cm is the radius of curvature

Therefore, solving the equation above for f, we find its focal length:

f=\frac{r}{2}=\frac{60.0 cm}{2}=30.0 cm

b) 90 cm

The mirror equation is:

\frac{1}{s'}=\frac{1}{f}-\frac{1}{s}

where

s' is the distance of the image from the mirror

f is the focal length

s is the distance of the object from the mirror

For the situation in the problem, we have

f = +30.0 cm is the focal length (positive for a concave mirror)

s = 45.0 cm is the object distance from the mirror

Solving the formula for s', we find

\frac{1}{s'}=\frac{1}{30.0 cm}-\frac{1}{45.0 cm}=0.011 cm^{-1}

s'=\frac{1}{0.011 cm^{-1}}=90 cm

c) -2

The magnification of the mirror is given by

M=-\frac{s'}{s}

where in this problem we have

s' = 90 cm is the image distance

s = 45.0 cm is the object distance

Solving the equation, we find:

M=-\frac{90 cm}{45 cm}=-2

So, the magnification is -2.

d) -12.0 cm

The magnification can also be rewritten as

M=\frac{y'}{y}

where

y' is the height of the image

y is the heigth of the object

In this problem, we know

y = 6.0 cm is the height of the object

M = -2 is the magnification

Solving the equation for y', we find

y'=My=(-2)(6.0 cm)=-12.0 cm

and the negative sign means that the image is inverted.

Part e and f are exactly identical as part b) and c).

6 0
4 years ago
Problem 3 A wire of length 16cm is suspended by flexible leads above a long straight wire. Equal but opposite currents are estab
oksian1 [2.3K]

Answer:

Option B

Solution:

As per the question:

Length of the suspended wire, l = 16 cm = 0.16 m

Distance between the long wire and the suspended wire, R = 1.5 mm = 0.0015 m

Mass of the 16 cm wire, m = 0.014 kg

Now,

We know that the magnetic field due to the two parallel current carrying straight long wires with current 'I' and the separation 'R' between the wires is given by:

B = \frac{\mu_{o}I}{2\pi R}                  (1)

If the suspended wire floats, force due to its weight is balanced by the magnetic force due to current I:

mg = IBl

Also, from eqn (1):

mg = I\frac{\mu_{o}I}{2\pi R}l

mg = \frac{\mu_{o}I^{2}l}{2\pi R}

0.014\times 9.8 = I\frac{4\pi \times 10^{- 7}I}{2\pi \times 0.0015}\times 0.16

I^{2} = 6430.436

I = 80.19 A

I = 80 A (approx)

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3 years ago
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