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Lapatulllka [165]
3 years ago
13

Which best describes a difference between energy transformations in power plants and dams?

Chemistry
2 answers:
Irina-Kira [14]3 years ago
5 0
I think the answer would be the last option. The difference between the energy transformations in power plants and dams would be that dams are the ones who uses mechanical energy to produce electricity. It uses turbines to convert mechanical to electrical.
Fed [463]3 years ago
5 0

Answer:

The answer is A

Explanation:

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John dalton was the first person recorded as thinking that matter was ultimately composed of atoms. true or false
Alona [7]

<span>The statement is false. It was Democritus, a Greek philosopher, who first theorized that matter was ultimately composed of atoms. His ideas were not widely accepted in his time (460-370 B.C), but during the 19th century, John Dalton proposed this theory and gained broad acceptance.</span>

3 0
3 years ago
Read 2 more answers
It took many of the metals several minutes to begin to react. Once the reaction was initiated, several of these metals continued
notsponge [240]

Answer:

Passivation of Oxide layers of the metals.

Explanation:

Passivation is a non-electrolytic finishing process that makes most metals rust-resistant. The prosses removes free iron from the surface by using either nitric or citric acid. When this happens, it results to an inert, protective oxide layer that is very slow or less likely to chemically react with air and cause corrosion.

Passivity caused many of the metals several minutes to begin to react. Once the finishing process that makes metals less likely to react was eroded, reaction was initiated vigorously.

8 0
3 years ago
When researchers need to prepare many reactions for polymerase chain reaction (PCR) amplification, they often create a "master m
Margaret [11]

Answer:

The master mix contains the following reagents: dNTPs, DNA Polymerase, PCR buffer and MgCl2.

Explanation:

The DNA templates are the gene fragments to amplify by PCR, thereby they have to be added separately in each tube. Moreover, the primer pairs are specific for each gene, thereby they have to be added separately in each tube.  

Deoxynucleotide triphosphates (dNTPs) are the building blocks of the DNA molecules: dGTP, dATP, TTP, and dCTP.

The PCR buffer provides a suitable medium for the activity of the DNA polymerase, often it contains Tris-Hcl and KCl.

MgCl2 is a cofactor for the activity of the DNA Polymerase.

The DNA Polymerase is an enzyme that amplifies DNA by adding nucleotides to the 3' end.

6 0
4 years ago
A cylinder with a moveable piston contains 92g of Nitrogen. The external pressure is constant at 1.00 atm. The initial temperatu
kramer

Answer:

The work for the given process is (- 2263.4 J)

Explanation:

Given: Mass of nitrogen gas (N₂): w = 92 g, external pressure: P = 1 atm, Initial temperature: T₁ = 200 K, Final temperature: T₂ = 200 + 83 K = 283 K

Molar mass of N₂ gas: m = 28 g, Gas constant: R = 8.314 J.K⁻¹.mol⁻¹

The number of moles of N₂ gas = w ÷ m = 92 g ÷ 28 g/mol = 3.28 mole

<u>To find the initial volume (V₁) and final volume (V₂), we use the </u><u>ideal gas equation</u><u>:</u>

PV =nRT

V_{1}=nRT_{1}\div P  

V_{2}=nRT_{2}\div P  

<u>So the </u><u>Work</u>: W = - P \Delta V  

W = - P (V_{2} - V_{2}) = - P (\frac{nRT_{2}}{P} - \frac{nRT_{1}}{P})  

W = nRT_{1} - nRT_{2} = nR(T_{1} - T_{2})  

W = nR(T_{1} - T_{2})  

W = (3.28 mole)(8.314 J.K^{-1}.mol^{-1})(200 K - 283K)

W = (3.28)(8.314)(-83)

W = (- 2263.4 J)

<u>Therefore, the work for the given process: W = (- 2263.4 J)</u>

6 0
4 years ago
Element A has a mass of 0.444 grams and reacts with Element B via a combination reaction. The mass of the product is 0.988 grams
IRINA_888 [86]

Answer:

AB2

Explanation:

The following data were obtained from the question:

Mass of element A = 0.444 g

Molar mass of element A = 111 g/mol

Mass of the compound = 0.988 g

Molar mass of Element B = 68 g/mol

Next, we shall determine the mass of element B. This is shown below:

Mass of element B = Mass of the compound – Mass of Element A

Mass of element B = 0.988 – 0.444

Mass of element B = 0.544 g

Now, we can obtain the empirical formula for the compound formed as follow:

A = 0.444

B = 0.544

Divide by their molar mass.

A = 0.444/111 = 4×10¯³

B = 0.544/68 = 8×10¯³

Divide by the smallest

A = 4×10¯³ /4×10¯³ = 1

B = 8×10¯³/4×10¯³ = 2

Therefore, the empirical formula for the compound formed is AB2

7 0
4 years ago
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