The first thing to do is to calculate the new concentration of the solution after dilution. We do as follows:
M1V1 = M2V2
(3.0 M).006 L = M2 (18 L)
M2 = 0.001 M HNO3
When in solution it dissociated into ions as follows:
HNO3 = H+ + NO3-
[H+] = 0.001 M HNO3 ( 1 mol H+ / 1 mol HNO3 ) = 0.001 M H+
pH = -log[H+] = -log 0.001 = 3
Answer:
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Explanation:
The pH of a buffer solution containing acid of pKa 7.5 will be 8.1.
The pH of a solution indicates its acidity or basicity. A pH below 7 is acidic, while pH above 7 is basic. 7 is considered as the neutral value.
A buffer is a solution that has the ability to resist the change in pH when an acid or a base is added to it. The natural example of buffer is blood.
According to the question, pKa of acid = 7.5
If concentration of base is x then, concentration of acid will be x/4.
According to the Henderson–Hasselbalch equation,
pH = pKa + log [A⁻] / [HA]
pH = 7.5 + log [
]
pH = 7.5 + log 4 ⇒ 7.5 + 0.602
pH = 8.1
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Answer:
Molecular formula is C₂₆H₃₆O₄
Explanation:
The compound is 75.69 % C, 8.80 % H and 15.51 % O. This data means, that in 100 g of compound we have 75.69 g, 15.51 g and 8.80 g of, C, O and H, respectively. We know the molar mass of the compound, so we can work to solve the moles of each element.
In 100 g of compound we have 75.69 g C, 15.51 g O and 8.80 g H
In 412 g of compound we would have:
(412 . 75.69) / 100 = 311.8 of C
(412 . 15.51) / 100 = 63.9 g of O
(412 . 8.80) / 100 = 36.2 g of H
Now, we can determine the moles of each, that are contained in 1 mol of compound.
312 g / 12 g/mol 26 C
64 g / 16 g/mol = 4 O
36 g / 1 g/mol = 36 H
Molecular formula is C₂₆H₃₆O₄
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