Answer:
The thermal energy (heat) needed, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity 'c' from 20°C to 180°C is 160·m·c joules
Explanation:
The heat capacity, 'C', of a substance is the heat change, ΔQ, required by a given mass, 'm', of the substance to produce a unit temperature change, ΔT
∴ C = ΔQ/ΔT
ΔQ = C × ΔT
C = m × c
Where;
c = The specific heat capacity
ΔT = The temperature change = T₂ - T₁
∴ ΔQ = m × c × ΔT
Therefore, the thermal energy (heat) needed, ΔQ, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity, 'c' from 20°C to 180°C is given as follows;
ΔQ = m × c × (180° - 20°) = 160° × m·c
ΔQ = 160·m·c joules
Answer:
CH3COONa : CH3COOH = 1.74 : 1 (required to prepare a buffer at PH = 5)
Explanation:
Given that :
PH = 5
Calculate proportions of ethanoic acid and Sodium ethanoate to prepare Buffer solution
solution :
PH = Pka + Log ( CH3COONa / CH3COOH )
5.0 = 4.76 + Log ( CH3COONa / CH3COOH )
∴ Log ( CH3COONa / CH3COOH ) = 0.24
( CH3COONa / CH3COOH ) = 1.74
Therefore : CH3COONa : CH3COOH
1.74 : 1
Answer:
So as the mass of either object increases, the force of gravitational attraction between them also increases. If the mass of one of the objects is doubled, then the force of gravity between them is doubled. If the mass of one of the objects is tripled, then the force of gravity between them is tripled.
Answer:
17.5609grams
Explanation:
According to the question, a sample of mass 6.814 grams is added to another sample weighing 0.08753 grams i.e.
= 6.814 + 0.08753
= 6.90153 grams
The result of this mixture i.e. 6.90153 grams is divided into three equal parts i.e.
= 6.90153 ÷ 3
= 2.30051 grams
This means that each equal part weighs 2.30051 grams
One of the yield (2.30051 grams) is multiplied by 7.6335 times i.e.
= 2.30051 × 7.6335
= 17.56094309
Hence, the final mass is 17.5609grams