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Lana71 [14]
3 years ago
10

How do you solve #10

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0
LINEAR \: \: EQUATIONS \\ \\ \\ Given \: expression \: \: - \: \\ \\ \frac{7}{3} (2x + 3) + \frac{3}{4} ( \frac{x}{5} - \frac{15}{2} ) = \frac{11}{8} \\ \\ \frac{14x}{3} + \frac{21}{3} + \frac{3x}{20} - \frac{45}{8} = \frac{11}{8} \\ \\ \frac{14x}{3} + \frac{3x}{20} + \frac{21}{3} - \frac{45}{8} = \frac{11}{8} \\ \\ \frac{289x}{60} = \frac{11}{8} + \frac{45}{8} - \frac{21}{3} \\ \\ \frac{289x}{60} = \frac{56}{8} - \frac{21}{3} \\ \\ \frac{289x}{60} = 7 - 7 = 0 \\ \\ \frac{289x}{60} = 0 \\ \\ \\ \: \: \: \:|| \: \: \: x = 0 \: \: \:|| \: \: \: \: \: \: \: \: \: \: \: \: \: Ans.
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An investment of $100 is now valued at $149.18 the interest rate is 8% compounded continuously about how long has the money been
deff fn [24]

question: An investment of $100 is now valued at $149.18 the interest rate is 8% per year, compounded continuously about how long has the money been invested

Answer:

5.2 years

Step-by-step explanation:

Applying

A = P(1+R/100)ⁿ.......................... Equation 1

Where A = amount, P = principle, R = rate, n = time.

From the question,

Given: A = $149.18, P = $100, R = 8%

Substitute these values into equation 1 and solve for n

149.18 = 100(1+8/100)ⁿ

149.18/100 = (1+8/100)ⁿ

1.4918 = (1+0.08)ⁿ

1.4918 = (1.08)ⁿ

Taking the Logarithm of both side

Log(1.4918) = Log(1.08)ⁿ

Log(1.4918) = nLog(1.08)

n = Log(1.4918)/Log(1.08)

n = 0.1737/0.0334

n = 5.2 years.

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→ Can someone help me pls ←
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