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klemol [59]
3 years ago
6

if S = at² + bt + c, where S is the distance, and t is the time, find the correct unit of a, b and c​

Physics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

a is in units of \frac{m}{s^{2}}

b is in units of \frac{m}{s}

c is in units of m

Explanation:

We have the following expression:

S=at^{2}+bt+c

Where:

S is the distance, hence its unit is m (meters, assuming we are using the International System of Units)

t is the time, hence its unit is s (seconds)

So, the expression is rewritten as:

m=as^{2}+bs+c

Since the left side of the equation is in meters, the right side must be in meters as well.

In addition, in the right side we have terms that have to added, this means each term must be in meters:

- For the first term a must be in units of \frac{m}{s^{2}} in order to have meters.

- For the second term b must be in units of \frac{m}{s} in order to have meters.

- For the third term c must be in units of m in order to have meters.

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A concert loudspeaker suspended high off the ground emits 34 W of sound power. A small microphone with a 1.0 cm2 area is 44 m fr
rjkz [21]

Answer:

<u>Part A</u>

I = 1.4 mW/m²  

<u>Part B</u>

β = 91.46 dB

Explanation:

<u>Part A</u>

Sound intensity is the power per unit area of sound waves in a direction perpendicular to that area. Sound intensity is also called acoustic intensity.

For a spherical sound wave, the sound intensity is given by;

                                            I = \frac{P}{A}

                                            I = \frac{P}{4\pi r^{2}}

Where;

P is the source of power in watts (W)

I is the intensity of the sound in watt per square meter (W/m2)

r is the distance r away

Given:

P = 34 W,

A = 1.0 cm²

r = 44 m

The sound intensity at the position of the microphone is calculated to be;

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = 0.0013975 W/m²

                                 ≈  I = 0.0014 W/m² = 1.4 × 10⁻³ W/m²

                                     I = 1.4 mW/m²

The sound intensity at the position of the microphone is 1.4 mW/m².

<u>Part B</u>

Sound intensity level or acoustic intensity level is the level of the intensity of a sound relative to a reference value.  It is a a logarithmic quantity. It is denoted by β and expressed in nepers, bels, or decibels.

Sound intensity level is calculated as;  

                                    β = 10log_{10}\frac{I}{I_{0}}  dB

Where,

β is the Sound intensity level in decibels (dB)

I is the sound intensity;

I₀ is the reference sound intensity;

By pluging-in, I₀ is 1.0 × 10⁻¹² W/m²

           ∴        β = 10log_{10}\frac{1.4 * 10^{-3} W/m^{2}}{1.0 * 10^{-12} W/m^{2}}

                      β = 10log_{10} (1.4 * 10^{9})

                      β = 91.46 dB

The sound intensity level at the position of the microphone is 91.46 dB.                

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