Please help me I really need help!!! can someone please put this in order here are the options: Amplitude, Crest, Trough, and Wa
velength picture down below.
1 answer:
You might be interested in
Answer:
v = 4.264 m/s
Explanation:
It is given that,
Mass of the ball, m = 0.15 kg
Spring constant of the spring, k = 150 N/m
The spring is compressed by a distance, x = 0.05 m
The pellet's initial velocity is at an angle θ (θ < 90) above the horizontal.
Let v is the final speed of the projectile when it is at a distance h = 0.800 m below its initial height. It can be calculated using the conservation of energy as :
v = 4.264 m/s
So, the final speed of the projectile is 4.264 m/s. Hence, this is the required solution.
Answer:
The maximum height of the arrow is 42 (and the units given for the height)
Explanation:
Everything is easier if you make a graph, you can give values to t and replace that values in the function, for example:
When t=0
h(0)=26
If you give some values to t you can see how the trajectory of the arrow is (please look the graphic below)
Now, to find the maximum you have to find the derivative of the function that describes the height of the arrow:
Then you have to take the derivative, and equals to zero to find t:
-32t+32=0
-32t=32
t=1
That is in the time of 1 second the arrow has its maximum height.
Now you have to replace this value in the original function, to find the height of the arrow:
h(1)=-16+32+36
h(1)=42
