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harina [27]
3 years ago
8

water is useful for reducing friction between objects. However, you also learned that (due to friction) moving water causes roug

h rocks to become smooth. How can this be?
Physics
2 answers:
nikdorinn [45]3 years ago
7 0

Answer:

Water in rivers can carry rocks through the water and rub them against other rocks,which over a long period of time makes them smooth.

sertanlavr [38]3 years ago
4 0
Water in rivers can carry rocks through the water and rub them against other rocks, which over long periods of time makes them smooth.
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A student measured the maximum mass of salt that can dissolve in 100mL of water at five different temperatures. Which variable s
Wewaii [24]

Answer: The answer is B, The variable that should go on the x- axis is the temperature of water.

Explanation: In an experiment, we must have two variables; the independent variable and the dependent variable.

If the results of the experiment is reported in graphical format, the independent variable is plotted on the x axis while the dependent variable is plotted on the y axis.

In this case, the independent variable is the temperature of the water while the dependent variable is the mass of salt dissolved in 100 mL of water.

Therefore, the variable that should go on the x- axis is the temperature of water.

3 0
3 years ago
Power=170 watts time=20 seconds
Art [367]
The answer is w=p.t. Substitution:hz 110.20.
4 0
3 years ago
Oscilloscopes have parallel metal plates inside them to deflect the electron beam. These plates are called the deflecting plates
alexdok [17]

Answer:

1.6 pF

Explanation:

The capacitance of a parallel-plate capacitor in air is given by:

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of each plate

d is the separation between the plates

In this problem we have:

- Separation between the plates: d = 5.00 mm = 0.005 m

- Area of the plates: A = 3.00 cm \cdot 3.00 cm = 9.00 cm^2 = 9\cdot 10^{-4}m^2

Therefore, the capacitance is

C=\frac{(8.85\cdot 10^{-12}F/m)(9\cdot 10^{-4} m^2)}{0.005 m}=1.6\cdot 10^{-12} F=1.6 pF

8 0
4 years ago
Vector of magnitude 15 is added to a vector of magnitude 25. The magnitude of this sum
loris [4]

Explanation:

Given that,

Magnitude of vector A, |A| = 15

Magnitude of vector B, |B| = 25

We need to find the magnitude of this sum.

The maximum sum of the resultant vector,

R_{max}=|A_1|+|A_2|\\\\=15+25\\\\=45

The minimum sum of the resultant vector,

R_{min}=|A_1|-|A_2|\\\\=15-25\\\\=-10

So, the magnitude of this sum either 45 or -10.

6 0
3 years ago
a. 2.00kg object is subject to three force that gives acceleration a =8m/s^2 i +6m/s j if two of three forces are f1 =(30.0N)+(1
tekilochka [14]

By Newton's second law, the net force on the object is

∑ <em>F</em> = <em>m</em> <em>a</em>

∑ <em>F</em> = (2.00 kg) (8 <em>i</em> + 6 <em>j</em> ) m/s^2 = (16.0 <em>i</em> + 12.0 <em>j</em> ) N

Let <em>f</em> be the unknown force. Then

∑ <em>F</em> = (30.0 <em>i</em> + 16 <em>j</em> ) N + (-12.0 <em>i</em> + 8.0 <em>j</em> ) N + <em>f</em>

=>   <em>f</em> = (-2.0 <em>i</em> - 12.0 <em>j</em> ) N

8 0
3 years ago
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