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never [62]
3 years ago
12

Superman throws a boulder of weight 3800 n at an adversary on the surface of the earth, where the magnitude of the acceleration

due to gravity, g = 9.80 m/s2 . what horizontal force must superman apply to the boulder to give it a horizontal acceleration of 12.8 m/s2 ?
Physics
1 answer:
evablogger [386]3 years ago
5 0
The weight of the boulder is 3800 N, therefore its mass i s
3800/9.8 = 387.755 kg

If the horizontal acceleration is 12.8 m/s², then the horizontal force applied is
F = (387.755 kg)*(12.8 m/s²) = 4.963 x 10³ n = 4.963 kN

Answer: 4.963 kN
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11. A 3.8 kg object is lifted 12 meters. Approximately how much work is performed during the lifting?
Mademuasel [1]
Hope this answers your question!! Ask any help at anytime
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3 years ago
A bullet B of mass mB traveling with a speed v0 = 1400 m/s ricochets off a fixed steel plate A of mass mA. Let mA ≫ mB so that i
Greeley [361]

Answer:

Rebounce angle is 345°

Rebounce speed is 989.95m/s

Explanation:

Calculate the x  component of the velocity of the bullet before impact by using the following relation:

Vbx= Vb Cos thetha

Here,  is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°

Substituting

Vbx = Cos15 ×1400 = 1352.30m/s

Calculate the y component using the relation:

Vby = Vo Sin theta

Vby = sin 15° × 1400

Vby = 362.35m/s

The rebounce angle = 360 - incidence angle

Rebounce angle =( 360 - 15)° = 345°

The rebound speed V' = Vby - Vbx

V' = (1352.30 - 362.35)m/s

V' = 989.95 m/s

5 0
3 years ago
#1 a person weighs 540n on earth what is the persons mass.
bixtya [17]

Answer:

G on earth =10N/Kg

W= mg

540= m x 10

m = 540/10

m= 54 Kg

W= mg

W= 66 x 10

W= 660 N

G on moon =1.6 N/Kg

#1

W= mg

W= 54 x 1.6

W=86.4 N

#2

W=mg

W= 66 x 1.6

W= 105.6 N

8 0
2 years ago
Two people are carrying a uniform wooden board that is 3.00 m long and weighs 160 N. If one person applies an upward force equal
Amanda [17]

Answer:

0.9 meters

Solution:

In these type of questions there are two equations:

First one is Force Balance and second one is Torque Balance.

<u>Force Balance</u>

First equation is generally used to know the magnitude of the force applied.

Since they have to lift wooden board in order to carry it, therefore they have to apply a counter force to overcome its weight, which is 160 N.

So the net force applied by the two men in upward direction is 160 N.

The force applied by person 1 (as in the figure attached) is 60 N and by person 2 is F N. So,

60 + F = 160

∴ F = 100 N

<u>Torque Balance</u>

(<em>Torque is nothing but a twisting force that tends to cause rotation.</em>

<em>To calculate torque multiply the force applied with the perpendicular distance between axis of rotation and line of application of force</em>)

The second equation is generally used to know the position of the force applied.

Since they are carrying wooden board in horizontal position, therefore there is no net torque on the wooden board.

To calculate torque first of all choose the axis of rotation. Here, there is no rotation so you can choose any axis of rotation which can help you to calculate the distance of application of force. Here the axis of rotation is chosen as the axis perpendicular to the wooden board passing through the center of it.

Since torque of two person are opposing each other as one is in clockwise direction and other one is in anticlockwise direction, therefore, if they are equal then the net torque will become zero. So,

60 \times 1.5 = F \times x

60 \times 1.5 = 100 \times x

90 = 100 \times x

x = \frac{90}{100}

x = 0.9 meters

<em>( NOTE: If you apply force in the same half side then the torque won't oppose each other rather it will support each other)</em>

3 0
3 years ago
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