Answer:
The average surface temperature decreases the further you get from the Sun because the more distant planets receive less energy/heat/sunlight per square meter of their surface. This is because the energy from the Sun spreads out (becomes less concentrated) as you travel further from the source/Sun.
Explanation:
Answer:
the max is 2,500 or less
Explanation:
because you cant owe anymore
Answer:
Part a)
charge on each sphere is -1.95 micro coulomb
Part b)
For first sphere
excess charge
For second sphere
excess charge
For third sphere
absent charge
For third sphere
absent charge
Explanation:
Part a)
Since all the spheres are of identical size so the total charge of the sphere will divide equally on them
So we have
![q = \frac{Q_1 + Q_2 + Q_3 + Q_4}{4}](https://tex.z-dn.net/?f=q%20%3D%20%5Cfrac%7BQ_1%20%2B%20Q_2%20%2B%20Q_3%20%2B%20Q_4%7D%7B4%7D)
![q = \frac{2.2 \mu C + 4.2 \mu C - 7.4 \mu C - 6.8 \mu C}{4}](https://tex.z-dn.net/?f=q%20%3D%20%5Cfrac%7B2.2%20%5Cmu%20C%20%2B%204.2%20%5Cmu%20C%20-%207.4%20%5Cmu%20C%20-%206.8%20%5Cmu%20C%7D%7B4%7D)
![q = -1.95 \mu C](https://tex.z-dn.net/?f=q%20%3D%20-1.95%20%5Cmu%20C)
So charge on each sphere is -1.95 micro coulomb
Part b)
For first sphere
initial charge = 2.2 micro coulomb
final charge = -1.95 micro coulomb
excess charge = -1.95 - 2.2 = -4.15 micro coulomb
Q = Ne
![N = \frac{4.15\times 10^{-19}}{1.6 \times 10^{-19}}](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B4.15%5Ctimes%2010%5E%7B-19%7D%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D)
![N = 2.6 \times 10^{13}](https://tex.z-dn.net/?f=N%20%3D%202.6%20%5Ctimes%2010%5E%7B13%7D)
For second sphere
initial charge = 4.2 micro coulomb
final charge = -1.95 micro coulomb
excess charge = -1.95 - 4.2 = -6.15 micro coulomb
Q = Ne
![N = \frac{6.15\times 10^{-19}}{1.6 \times 10^{-19}}](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B6.15%5Ctimes%2010%5E%7B-19%7D%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D)
![N = 3.8 \times 10^{13}](https://tex.z-dn.net/?f=N%20%3D%203.8%20%5Ctimes%2010%5E%7B13%7D)
For third sphere
initial charge = -7.4 micro coulomb
final charge = -1.95 micro coulomb
absent charge = -1.95 + 7.4 = 5.45 micro coulomb
Q = Ne
![N = \frac{5.45\times 10^{-19}}{1.6 \times 10^{-19}}](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B5.45%5Ctimes%2010%5E%7B-19%7D%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D)
![N = 3.4 \times 10^{13}](https://tex.z-dn.net/?f=N%20%3D%203.4%20%5Ctimes%2010%5E%7B13%7D)
For third sphere
initial charge = -6.8 micro coulomb
final charge = -1.95 micro coulomb
absent charge = -1.95 + 6.8 = 4.85 micro coulomb
Q = Ne
![N = \frac{4.85\times 10^{-19}}{1.6 \times 10^{-19}}](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B4.85%5Ctimes%2010%5E%7B-19%7D%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D)
![N = 3.03 \times 10^{13}](https://tex.z-dn.net/?f=N%20%3D%203.03%20%5Ctimes%2010%5E%7B13%7D)
The answer to your question is it <span>absorbs ultraviolet light</span>
300g is what that is on which is equal to 10.58oz