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faust18 [17]
3 years ago
5

What makes west region different?

Physics
1 answer:
anzhelika [568]3 years ago
7 0

Answer:

The West is known for "wide, open spaces", cattle, mines, and mountains.

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The image shows a roller coaster.
mariarad [96]
I believe the answer is c but I’m not 100% sure
8 0
3 years ago
The vector product of vectors A⃗ and B⃗ has magnitude 12.0 m2 and is in the +z-direction.Vector A⃗ has magnitude 4.0 m and is in
g100num [7]

Answer:

θ=180°

Explanation:

The problem says that the vector product of A and B is in the +z-direction, and that the vector A is in the -x-direction. Since vector B has no x-component, and is perpendicular to the z-axis (as A and B are both perpendicular to their vector product), vector B has to be in the y-axis.

Using the right hand rule for vector product, we can test the two possible cases:

  • If vector B is in the +y-axis, the product AxB should be in the -z-axis. Since it is in the +z-axis, this is not correct.

  • If vector B is in the -y-axis, the product AxB should be in the +z-axis. This is the correct option.

Now, the problem says that the angle θ is measured from the +y-direction to the +z-direction. This means that the -y-direction has an angle of 180° (half turn).

8 0
3 years ago
Which three statements about electromagnetic radiation are true?
grandymaker [24]
I think that numbers one, three, and four are true
3 0
3 years ago
Read 2 more answers
Two identical charges,2.0m apart,exert forces of magnitude 4.0 N on each other.What is the value of either charge?
storchak [24]

Answer:

\large \boxed{42\, \mu \text{C}}$

Explanation:

The formula for the force exerted between two charges is

F=k \dfrac{ q_1q_2}{r^2}

where k is the Coulomb constant.

The charges are identical, so we can write the formula as

F=k\dfrac{q^{2}}{r^2}

\begin{array}{rcl}\text{4.0 N}& = & 8.988 \times 10^{9}\text{ N$\cdot$m$^{2}$C$^{-2}$} \times \dfrac{q^{2}}{\text{(2.0 m)}^{2}}\\\\4.0 & = & 2.25 \times 10^{9}\text{ C$^{-2}$} \times q^{2}\\\\q^{2} & = & \dfrac{4.0}{2.25 \times 10^{9}\text{ C$^{-2}$}}\\\\& = & 1.78 \times 10^{-9} \text{ C}^{2}\\q & = & 4.2 \times 10^{-5} \text{ C}\\& = & 42\, \mu \text{C}\\\end{array}\\\text{Each charge has a value of $\large \boxed{\mathbf{42\, \mu }\textbf{C}}$}

7 0
3 years ago
A car speeds up from 13 m/s to 23 m/s in 30 seconds. What is the
Lapatulllka [165]

acceleration of the car = 0.33 m/s²

Explanation:

To calculate the acceleration of the car we use the following formula:

acceleration = change in velocity / time

change in velocity = final velocity - initial velocity

change in velocity = 23 m/s - 13 m/s = 10 m/s

change in velocity = 10 m/s

acceleration = 10 m/s / 30 s

acceleration = 0.33 m/s²

Learn more about:

acceleration

brainly.com/question/4134594

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#learnwithBrainly

8 0
3 years ago
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