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3 years ago

7. Calculate the gravitational potential energy of a 10 kg box on the top shelf of a closet, 2 m above the floor.

Physics

1 answer:

snow_lady [41]3 years ago

5 0

Answer:

P.E = 196 J

Explanation:

Given,

The mass of the box, m = 10 Kg

The height of the box from the ground, h = 2 m

The acceleration due to gravity, a = 9.8 m/s²

The gravitational potential energy of the box is given by the formula

P.E = mgh joules

Substituting the given values in the above equation,

P.E = 10 x 2 x 9.8

= 196 J

Hence, the gravitational potential energy of box, P.E = 196 J

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If current I=2A and resistance R= 5 ohms what is the potential difference (voltage) V?

damaskus [11]

Answer:

10 V

Explanation:

From Ohm's law, V=IR where V is the potential difference voltage, I is the current and R is resistance. Substituting 2A for current and 5 Ohms for resistance then V=2*5= 10 V

6 0

3 years ago

A packet is dropped from a stationary helicopter, hovering at a height 'h' from the ground level, reaches the ground in 12s. Cal

Ksju [112]

Use kinematic equations to solve:

1) yf = yo + vo*t + 1/2at²

yf = final height
yo = initial height
vo = initial velocity
a = acceleration
t = time

yf - yo = vo*t + 1/2at²

yf - yo = h

vo = 0

Thus,

h = 1/2at²

h = 1/2(9.8)(12)² = 705.6 m

2) vf = vo + at

vo = 0

Thus,

vf = at

vf = (9.8)(12) = 117.6 m/s

4 0

4 years ago

Three beads are placed along a thin rod. The first bead, of mass m1 = 23 g, is placed a distance d1 = 1.1 cm from the left end o

Mila [183]

Answer:

a) $x=\frac{m_{1}d_{1}+m_{2}(d_{1}+d_{2})+m_{3}(d_{1}+d_{2}+d_{3} ) }{m_{1}+m_{2}+m_{3} }$

b) x = 4.47 cm

c) $x=\frac{m_{1}d_{2}+m_{2}(0)+m_{3}d_{3} }{m_{1}+m_{2}+m_{3} }$

d) x = 1.48 cm

Explanation:

a) The center of mass is equal to:

$x=\frac{m_{1}x_{1}+m_{2}x_{2}+m_{3}x_{3} }{m_{1}+m_{2} +m_{3}}$

Where m is the mass of beads and x is the distances, if x₁ = d₁, x₂ = d₂ and x₃ = d₃

$x=\frac{m_{1}d_{1}+m_{2}(d_{1}+d_{2})+m_{3}(d_{1}+d_{2}+d_{3} ) }{m_{1}+m_{2}+m_{3} }$

b) If

m₁ = 23g

m₂ = 15 g

m₃ = 58 g

d₁ = 1.1 cm

d₂ = 1.9 cm

d₃ = 3.2 cm

$x=\frac{23*1.1+15*(1.1+1.9)+58(1.1+1.9+3.2) }{23+15+58 } =4.47cm$

c) The center of the mass of the beads realtive to the center of bead is:

$x=\frac{m_{1}d_{2}+m_{2}(0)+m_{3}d_{3} }{m_{1}+m_{2}+m_{3} }$

d) $x=\frac{23*(-1.9)+(15*0)+(58*3.2) }{23+15+58 } =1.48cm$

6 0

3 years ago

Read 2 more answers

How does the rate of groundwater flow compare with that of ocean currents or river currents? Choose one: A. The rate of groundwa

ioda

Answer:

A. The rate of groundwater flow is faster than that of surface-water currents

Explanation:

A velocity of 1 foot per day or greater is a high rate of movement for ground water, and ground-water velocities can be as low as 1 foot per year or 1 foot per decade. In contrast, velocities of streamflow generally are measured in feet per second.

Horizontal movements are called currents, which range in magnitude from a few centimetres per second to as much as 4 metres (about 13 feet) per second. A characteristic surface speed is about 5 to 50 cm (about 2 to 20 inches) per second.

An ocean current is any more or less permanent or continuous, directed movement of ocean water that flows in one of the Earth's oceans. The currents are generated from the forces acting upon the water like the earth's rotation, the wind, the temperature and salinity differences and the gravitation of the moon

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4 years ago

What factors determine if an earthquake can be classified as an induced earthquake?

Luba_88 [7]

Answer:1 }The state of stress of the earth's crust

2}Existing faults

Explanation:

6 0

1 year ago