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Vikentia [17]
3 years ago
11

7. Calculate the gravitational potential energy of a 10 kg box on the top shelf of a closet, 2 m above the floor.

Physics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

P.E = 196 J

Explanation:

Given,

The mass of the box, m = 10 Kg

The height of the box from the ground, h = 2 m

The acceleration due to gravity, a = 9.8 m/s²

The gravitational potential energy of the box is given by the formula

                              P.E = mgh joules

Substituting the given values in the above equation,

                              P.E = 10 x 2 x 9.8

                                   = 196 J

Hence, the gravitational potential energy of box, P.E = 196 J

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Read 2 more answers
Two identical tiny spheres of mass m =2g and charge q hang from a non-conducting strings, each of length L = 10cm. At equilibriu
Citrus2011 [14]

Answer:

0.247 μC

Explanation:

As both sphere will be at the same level at wquilibrium, the direction of the electric force will be on the x axis. As you can see in the picture below, the x component of the tension of the string of any of the spheres should be equal to the electric force of repulsion. And its y component will be equal to the weight of one sphere. We can use trigonometry to find the components of the tensions:

F_y:  T_y - W = 0\\T_y = m*g = 0.002 kg *9.81m/s^2 = 0.01962 N

T_y = T_*cos(50)\\T = \frac{T_y}{cos(50)} = 0.0305 N

T_x = T*sin(50) = 0.0234 N

The electric force is given by the expression:

F = k*\frac{q_1*q_2}{r^2}

In equilibrium, the distance between the spheres will be equal to 2 times the length of the string times sin(50):

r = 2*L*sin(50) = 2 * 0.1m * sin(50) 0.1532 m

And k is the coulomb constan equal to 9 *10^9 N*m^2/C^2. q1 y q2 is the charge of each particle, in this case, they are equal.

F_x = T_x - F_e = 0\\T_x = F_e = k*\frac{q^2}{r^2}

q = \sqrt{T_x *\frac{r^2}{k}} = \sqrt{0.0234 N * \frac{(0.1532m)^2}{9*10^9 N*m^2/C^2} } = 2.4704 * 10^-7 C

O 0.247 μC

8 0
3 years ago
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