The best estimate would be around 350,000 to 450,000
Answer:
B. and E.
Step-by-step explanation:
In pure translation or in roll without slip?
In pure translation, just use Fnet = m*a. Fnet = 7.5 Newtons
In roll without slip it has effectively more inertia than 5 kilograms. The effective inertia can be found as:
m_effective = m + I/r^2
For a uniform solid sphere, I = 2/5*m*r^2
So m_effective = 7/5*m
To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).
i hope this is what ur looking for
$1 = 3.70 rands
$450 is simply 450 times $1, so multiply the conversion equation above by 450 on both sides.
450 * $1 = 450 * 3.70 rands
$450 = 1665 rands
Answer: 8 UK£
Step-by-step explanation:
