Answer:
Power=720[watt]
Explanation:
We need to remember the definition of mechanical work which is equal to the product of the force applied by the distance traveled.
In this problem, we have to find the power which is defined as the work divided into the time in which such work is performed. This way if we have the displacement and the time, this will be the speed with which this work is done.
![Power= W/T\\T=time [s]\\W=work [J]\\Power = F*V\\where\\V=velocity [m/s]\\Power=1800 * 0.4 = 720 [watt]](https://tex.z-dn.net/?f=Power%3D%20W%2FT%5C%5CT%3Dtime%20%5Bs%5D%5C%5CW%3Dwork%20%5BJ%5D%5C%5CPower%20%3D%20F%2AV%5C%5Cwhere%5C%5CV%3Dvelocity%20%5Bm%2Fs%5D%5C%5CPower%3D1800%20%2A%200.4%20%3D%20720%20%5Bwatt%5D)
Answer:

From Newton's 2nd Law, we have
. Substituting given values, we have:

Answer:
46.9 C
Explanation:
The heat released by the gold bar is equal to the heat absorbed by the water:

where:
is the mass of the gold bar
is the specific heat of gold
is the initial temperature of the gold bar
is the mass of the water
is the specific heat of water
is the initial temperature of the water
is the final temperature of both gold and water at equilibrium
We can re-arrange the formula and solve for T_f, so we find:

The 50N group of force would be greater
So whichever object is being pulled will be pulled towards the 50N force