To solve the exercise it is necessary to use the reciprocal Lorenz factor of the special theory of relativity with the pulse rate.
Where,
Pulse rate measured by earth observed
Reciprocal Lorenz Factor
Here v is the velocity and c the light speed.
PART A) For the given values we can replace it at the previous equation,
PART B ) If the speed of vehicle is 0.94c:
Answer:
The distance can the water be projected is 4.51 m
Explanation:
The speed of the water in the hose is equal to:
v1 = R/A1
If we solve the continuity for v2:
v2 = R/A2 (eq. 1)
The equation for the vertical position is:
yf = yi + vy*t - (1/2)gt²
yi = 0
vy = 0
Clearing t:
(eq. 2)
The equation for position is:
xf = xi + vxt = 0 + v2t = v2t (eq. 3)
Replacing equation 1 and 2 in equation 3:
Explanation:
The given data is as follows.
width = 100 m, speed = 3 m/s
So, minimum time required to cross the stream is calculated as follows.
t =
Also, in the same time the man has moved downstream by 50 meter.
Hence, distance traveled downstream is as follows.
d = velocity of river × t
=
=
= 1.5 m/s
Thus, we can conclude that the river is flowing by 1.5 m/s.