Review the families and classification of elements in the periodic table. Based on this information, you would expect elements t
2 answers:
You might be interested in
Hoffman Product is always a less substituted alkene. In given scenario Structure A (Given Below) was taken as a starting chiral Amine. For the sake of elimination the amine was taken tertiary so that on methylation it becomes a good leaving group. This chiral amina (A) when treated with Methyl Iodide gives a quarternary amine which on treatment with Silver oxide yields less substituted Alkene (B) as shown Below.
Alkene B on Ozonolysis give two aldehydes i.e. Formaldehyde and Butyraldehyde.
Alkene B on Ozonolysis give two aldehydes i.e. Formaldehyde and Butyraldehyde.