Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g
% LI = 13.88/73.89*100 = 18.78% perfectly correct.
Given :
10 gram sample of propane( C₂H₈ ).
To Find :
The number of moles of propane in given sample.
Solution :
Molecular mass of propane, M = (2 × 12) + ( 1 × 8 ) gram/mol
M = 32 gram/mol
We know, number of moles is given by :
Number of moles, n = m/M
n = 10/32 mol
n = 0.3125 mol
Therefore, number of moles in given sample is 0.3125 mol.
Answer:
<h3>The answer is 43.48 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 500 g
volume = 11.5 cm³
We have

We have the final answer as
<h3>43.48 g/cm³</h3>
Hope this helps you