<h3>
Answer:</h3>
35 meters
<h3>
Explanation:</h3>
<u>Data given;</u>
- Velocity of an object = 5 m/s
- Time taken = 7 s
We are required to calculate how far the object traveled.
Velocity = Displacement ÷ time
Displacement = Velocity × time
= 5 m/s × 7 s
= 35 m
Therefore; the object traveled 35 meters
Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2