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Crazy boy [7]
4 years ago
10

An object is dropped from 26 feet below the tip of the pinnacle atop a 702 ft tall building. The height h of the object after t

seconds is given by the equation h=-16t^2+676. Find how many seconds pass before the object reaches the ground.
Physics
1 answer:
Dimas [21]4 years ago
4 0

Answer:

6.5 seconds.

Explanation:

Given: h=-16t²+679

When the object reaches the ground, h=0.

∴ 0=-16t²+679

collecting like terms,

⇒ 16t²=679

Dividing both side of the equation by the coefficient of t² i.e 16

⇒ 16t²/16 = 679/16

⇒ t² = 42.25

taking the square root of both side of the equation.

⇒ √t² =√42.25

⇒ t = 6.5 seconds.

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9

Explanation:

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Find the Gravitational Potential at a point on the earth’s surface. Take mass of earth as 5.98 X 10 24 kg, its radius as 6.38 X
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-6.25 x 10^7 J/Kg\\\\

Explanation:

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An underwater scuba diver looks up toward the water's surface. She sees a buoy floating on the surface and notes its location. S
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As here the scuba driver is looking from an optically denser medium to an optically rarer medium the boy may appear nearer to the diver in position than is actually in the air.

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n=\frac{sin\ i}{sin\ r}

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8 0
3 years ago
Suppose that the separation between two speakers A and B is 4.80 m and the speakers are vibrating in-phase. They are playing ide
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\lambda/2=1.27037037

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X=8.44m

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object in motion stays in motion, object at rest stays at rest unless acted upon an unbalanced force
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