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4 years ago

What is 79,531 using number words?

Mathematics

2 answers:

Romashka [77]4 years ago

5 0

Hi there!

The following number in words will be,

Seventy nine thousand, five hundred thirty one.

Hope this helped!~

lukranit [14]4 years ago

4 0

Hello!

79,531 is pronounced seventy-nine, thousand, five hundred and thirty-one.

Hope this helps! ~Pooch ♥

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Hoochie [10]

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3 years ago

Read 2 more answers

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

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4 years ago

Running times for 400 meters are Normally distributed for young men between 18 and 30 years of age with a mean of 93 seconds and

kkurt [141]

Answer: The running time should at least 119.32 seconds to be in the top 5% of runners.

Step-by-step explanation:

Let X= random variable that represents the running time of men between 18 and 30 years of age.

As per given, X is normally distrusted with mean $\mu=93\text{ seconds}$ and standard deviation $\sigma=16\text{ seconds}$ .

To find: x in top 5% i.e. we need to find x such that P(X<x)=95% or 0.95.

i.e. $P(\dfrac{X-\mu}{\sigma}$

$P(Z$

Since, z-value for 0.95 p-value ( one-tailed) =1.645

So,

Hence, the running time should at least 119.32 seconds to be in the top 5% of runners.

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3 years ago

Vertex A in quadrilateral ABCD lies at (-3, 2). If you rotate ABCD 180° clockwise about the origin, what will be the coordinates

Leni [432]

Answer:

A. (3, -2)

Step-by-step explanation:

A 180° rotation about the origin places an object in the quadrant diagonal to the one it started in. Moving the object two 90° turns, will place it in a coordinate that will make the values of 'x' and 'y' opposite to the initial value. In this case, vertex A has an initial point of (-3, 2), so after a 180° rotation, it would be (3, -2).

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4 years ago